TypeError：在Tkinter中需要一個整數（獲得類型str）

Question

因此，我正在編寫一個應用程序，它允許您存儲您提供給列表框的信息，該列表框還可用於在某處打印數據。 （創建一個txt並存儲它。）我也嘗試了以前用戶發佈的所有建議，但找不到我的案例。任何幫助讚賞。

出於某種原因，我在標題中看到了錯誤。

這裏是我的代碼：

from tkinter import* 
from os import open 

def addData(): 
    dataInsert = dataEntry.get() 
    itemList.insert(END, dataInsert.upper()) 
    dataEntry.delete(0, END) 

def deleteData(): 
    dataSelect = itemList.curselection() 
    itemList.delete(dataSelect) 

def clearData(): 
    itemList.delete(0, END) 

def printData(): 
    dataDirectory = filedialog.askdirectory() 
    f = open('items.txt', dataDirectory, 'ab+') 
    f.write(bytes('', itemList.get(), 'UTF-8')) 
    f.close() 

def rootExit(): 
    root.destroy() 

root = Tk() 
root.config(bg='gray79') 
root.title('Inventory Recording Systems') 
root.geometry('1300x800') 
root.resizable(width=False, height=False) 

mainLabel = Label(text='Inventory Recording Systems', 
        font=('comic sans ms', 20, 'bold'), 
        bg='gray79', 
        fg='black') 

mainLabel.place(x=360, y=10) 

f1 = Frame(root, 
      bg='black', 
      width=300, 
      height=40) 

f1.place(x=40, y=22) 

f2 = Frame(root, 
      bg='black', 
      width=300, 
      height=40) 

f2.place(x=950, y=22) 

dataLabel = Label(root, 
        text='Enter Data:', 
        font=('comic sans ms', 20, 'bold'), 
        bg='gray79') 

dataLabel.place(x=10, y=130) 

dataEntry = Entry(root, 
        font=('arial', 16, 'bold')) 

dataEntry.place(x=250, y=142) 

itemList = Listbox(root, 
        font=('arial', 15, 'bold'), 
        width=47, 
        height=16) 

itemList.place(x=10, y=200) 

addButton = Button(root, 
        text='Add Data', 
        font=('arial', 20, 'bold'), 
        bg='gray89', 
        fg='black', 
        relief=GROOVE, 
        width=15, 
        height=1, 
        bd=5, 
        command=addData) 

addButton.place(x=865, y=215) 

deleteButton = Button(root, 
        text='Delete Data', 
        font=('arial', 20, 'bold'), 
        bg='gray89', 
        fg='black', 
        relief=GROOVE, 
        width=15, 
        height=1, 
        bd=5, 
        command=deleteData) 

deleteButton.place(x=865, y=345) 

clearButton = Button(root, 
        text='Clear Data', 
        font=('arial', 20, 'bold'), 
        bg='gray89', 
        fg='black', 
        relief=GROOVE, 
        width=15, 
        height=1, 
        bd=5, 
        command=clearData) 

clearButton.place(x=865, y=470) 

printButton = Button(root, 
        text='Print Data', 
        font=('arial', 20, 'bold'), 
        bg='gray89', 
        fg='black', 
        relief=GROOVE, 
        width=15, 
        height=1, 
        bd=5, 
        command=printData) 

printButton.place(x=865, y=595) 

exitButton = Button(root, 
        text='Exit', 
        font=('arial', 10, 'bold'), 
        bg='gray89', 
        fg='black', 
        relief=GROOVE, 
        width=6, 
        height=1, 
        bd=5, 
        command=rootExit) 

exitButton.place(x=1212, y=752) 

root.mainloop() 

Answer 1

，因爲你的打印功能，試圖以這種形式打開一個文件你收到這個錯誤。 os中的open函數按照該順序接受文件名，模式，緩衝區。這是你的腳本中的內容：

f = open('items.txt', dataDirectory, 'ab+') 

你正在傳遞（文件名，路徑，模式）。相反，你應該這樣做：

f = open(dataDirectory+'/items.txt', mode='a') 

順便說一句，你仍然有錯誤，你如何寫作。我建議你閱讀OS項目文檔和其在Python 3.轉到您的終端使用和運行這個：也

import os 
help(os) 

，請閱讀本article，它會幫助你從蟒蛇2遷移代碼3並將幫助您發現遷移的潛在問題。該段在你的情況特別有趣的是這個：

As part of this dichotomy you also need to be careful about opening files. Unless you have been working on Windows, there is a chance you have not always bothered to add the b mode when opening a binary file (e.g., rb for binary reading). Under Python 3, binary files and text files are clearly distinct and mutually incompatible; see the io module for details. Therefore, you must make a decision of whether a file will be used for binary access (allowing binary data to be read and/or written) or textual access (allowing text data to be read and/or written). You should also use io.open() for opening files instead of the built-in open() function as the io module is consistent from Python 2 to 3 while the built-in open() function is not (in Python 3 it’s actually io.open()). Do not bother with the outdated practice of using codecs.open() as that’s only necessary for keeping compatibility with Python 2.5.

Answer 2

參數編碼具有這樣

此代碼需要重新編寫爲

f.write(bytes('', itemList.get(), 'UTF-8')) 

爲

傳遞

f.write(bytes('', itemList.get(), encoding='UTF-8'))