用Python結束程序

Question

我很努力地用Python結束我的程序，我只想輸入q或quit來結束程序。這是我的代碼

# This is a guess the number game 
import random 

guessesTaken = 0 

print('Hello! What is your name?') 
myName = input() 

number = random.randint(1, 20) 
print('Well, ' + myName + ', I am thinking of a number between 1 and 20, can  you guess it?') 

while guessesTaken < 6: 
    print('Take a guess!') 
    guess = input() 
    guess = int(guess) 

    guessesTaken = guessesTaken + 1 

    if guess < number: 
     print('Your guess is too low') 

    if guess > number: 
     print('Your guess is too high') 

    if guess == number: 
     break 

if guess == number: 
    guessesTaken = str(guessesTaken) 
    print('Good job ' + myName + '!You guessed my number in ' + guessesTaken + ' guesses!') 

    if guess != number: 
     number = str(number) 
     print('Nope. The number I was thinking of was ' + number) 

     print('Game Over') 
     choice = input('Press Q to Quit') 
     if choice == 'q' : 
     sys.exit() 

請告訴我我要去哪裏錯？

Answer 1

從我能告訴你有兩個錯誤。

首先，您需要導入sys模塊以使sys.exit()正常工作。

其次，你的縮進在兩個地方是不正確的。這是正確的代碼。該言論表明，其中的壓痕不正確：

# This is a guess the number game 
import random 
import sys 

guessesTaken = 0 

print('Hello! What is your name?') 
myName = input() 

number = random.randint(1, 20) 
print('Well, ' + myName + ', I am thinking of a number between 1 and 20, can  you guess it?') 

while guessesTaken < 6: 
    print('Take a guess!') 
    guess = input() 
    guess = int(guess) 

    guessesTaken = guessesTaken + 1 

    if guess < number: 
     print('Your guess is too low') 

    if guess > number: 
     print('Your guess is too high') 

    if guess == number: 
     break 

if guess == number: 
    guessesTaken = str(guessesTaken) 
    print('Good job ' + myName + '!You guessed my number in ' + guessesTaken + ' guesses!') 

if guess != number: #indentation was off here 
    number = str(number) 
    print('Nope. The number I was thinking of was ' + number) 

print('Game Over') #and here 
choice = input('Press Q to Quit') 
if choice == 'q' : 
    sys.exit() # and here 

Answer 2

由於@MarkyPython指出，你有一些縮進錯誤，你需要導入SYS，如果你想使用退出。 請注意，考慮到您擁有的代碼，使用sys.exit()實際上是不好的做法。我會建議您使用break。這將退出你的while循環。因爲你之後沒有任何代碼，你的程序會優雅地退出。

如果您稍後添加更多代碼，您可能需要將代碼放入函數中。在那一點上，使用return將是一條路。

使用break或return是更好的做法，因爲它更容易在稍後向程序中添加功能並使代碼更好地流動（不會突然退出「跳躍」）。

print('Hello! What is your name?') 
myName = input() 

number = random.randint(1, 20) 
print('Well, ' + myName + ', I am thinking of a number between 1 and 20, can  you guess it?') 

while guessesTaken < 6: 
    print('Take a guess!') 
    guess = input() 
    guess = int(guess) 

    guessesTaken = guessesTaken + 1 

    if guess < number: 
     print('Your guess is too low') 

    if guess > number: 
     print('Your guess is too high') 

    if guess == number: 
     break 

    if guess == number: 
     guessesTaken = str(guessesTaken) 
     print('Good job ' + myName + '!You guessed my number in ' + guessesTaken + ' guesses!') 

    if guess != number: 
     number = str(number) 
     print('Nope. The number I was thinking of was ' + number) 

     print('Game Over') 
     choice = input('Press Q to Quit') 
     if choice == 'q' : 
      break # instead of exit