爲什麼preg_match（）在某些情況下不匹配

Question

這裏我使用的代碼適用於所有其他輸入，但不適用於hospital爲什麼？

如果你建議任何其他過濾器，那麼這將是非常感激。

觀看演示：http://phpio.net/s/cgv

這裏是我的代碼：

$type = strtolower("hospital"); 

if(preg_match('/it|IT|it services|it service|it infrastructure|it infrastructures/',$type)){ 
    $img = "images/it1-200x111.jpg"; 
}else if(preg_match('/business|business solutions|biz solutions|business solution|biz solution/',$type)){ 
    $img = "images/business-200x111.jpg"; 
}else if(preg_match('/manpower|manpower solution|manpower solutions|manpower services|manpower service|human resource|human resources/',$type)){ 
    $img = "images/mp-1-200x111.jpg"; 
}else if(preg_match('/financial|finance|financial solution|financial solutions|financial service|financial services/',$type)){ 
    $img = "images/fin-200x111.jpg"; 
}else if(preg_match('/marketing|marketing solution|marketing solutions|marketing service|marketing services/',$type)){ 
    $img = "images/mark1-200x111.jpg"; 
}else if(preg_match('/real estate|real estates|real estate solution|real estates solution|real estate solutions/',$type)){ 
    $img = "images/real1-200x111.jpg"; 
}else if(preg_match('/school|schooling services|school services|schools service|schooling service/',$type)){ 
    $img = "images/school1-200x111.jpg"; 
}else if(preg_match('/college|college service|college services|colleges/',$type)){ 
    $img ="images/coll1-200x111.jpg"; 
}else if(preg_match('/hospital|hospitals|hospital service|hospital services/',$type)){ 
    $img = "images/hosp-1-200x111.jpg"; 
}else{ 
    $img = "images/it1-200x111.jpg"; 
} 

echo $img; 

Answer 1

hospital相匹配的第一個條件，因爲有it那裏。 嘗試在條件上添加開始/開始符號^。例如^it，它只會在字符串以it開頭時匹配。