MySQL SELECT Query - 減去一個SUM（）值與其他兩個SUM（）值的總和

Question

我有兩個SELECT語句給出值「TotalSales」和「VendorPay_Com」。我希望能夠從一個MySQL語句中的TotalSales中減去VendorPay_Com以獲得值「Outstanding_Funds」，但我還沒有找到一個可靠的方法來做到這一點。

這些是我的兩個語句：

查詢1：

SELECT SUM(Price) AS TotalSales 
FROM PROPERTY 
WHERE Status = 'Sold'; 

查詢2：

SELECT SUM(AC.Amount) AS VendorPay_Comm 
FROM (
SELECT Amount FROM lawyer_pays_vendor 
UNION ALL 
SELECT CommissionEarned AS `Amount` FROM COMMISSION AS C WHERE C.`status` = 'Paid') AS AC 

在這個問題上的任何幫助，將不勝感激:)

Answer 1

如下你可以這樣做：

select (select ...) - (select ...) 

在您的例子，簡單地說：

select 

(
SELECT SUM(Price) AS TotalSales 
FROM PROPERTY 
WHERE Status = 'Sold' 
) 
- 
(
SELECT SUM(AC.Amount) AS VendorPay_Comm 
FROM (
SELECT Amount FROM lawyer_pays_vendor 
UNION ALL 
SELECT CommissionEarned AS `Amount` FROM COMMISSION AS C WHERE C.`status` = 'Paid') AS AC 
) AS Outstanding_Funds 

Answer 2

嘗試

SELECT TotalSales-VendorPay_Comm AS Outstanding_Funds 
    FROM 
(SELECT SUM(Price) AS TotalSales 
    FROM PROPERTY 
    WHERE Status = 'Sold') t1, 
(SELECT SUM(Amount) AS VendorPay_Comm 
    FROM (SELECT Amount FROM lawyer_pays_vendor 
      UNION ALL 
     SELECT CommissionEarned AS Amount 
      FROM COMMISSION 
      WHERE Status = 'Paid') t0) t2 

這裏是sqlfiddle