不能在Php

Question

我在客戶端服務器套接字程序工作就像應用程序創建的聊天客戶端服務器的Socket程序，但它給下面的錯誤消息

警告：socket_bind（）：無法綁定地址[ 98]：地址已在使用....無法綁定到第15行上的地址

我已經看到各種教程，但我希望服務器不斷收聽客戶端請求。我看到它的端口號也是開放的，但仍然是相同的信息。我在這一點卡住了幾天無法得到適當的解決方案。請幫助解決這個問題.....感謝

Server.php：

<?php 
    error_reporting(E_ALL); 

    /* Allow the script to hang around waiting for connections. */ 
    set_time_limit(0); 

    /* Turn on implicit output flushing so we see what we're getting 
    * as it comes in. */ 
    ob_implicit_flush(); 

    $address = 'XXX.XX.XX.XXX'; 
    $port = 15213; 

    if (($sock = socket_create(AF_INET, SOCK_STREAM, SOL_TCP)) === false) { 
     echo "socket_create() failed: reason: " . socket_strerror(socket_last_error()) . "\n"; 
    } 

    if (socket_bind($sock, $address, $port) === false) { 
     echo "socket_bind() failed: reason: " . socket_strerror(socket_last_error($sock)) . "\n"; 
    } 

    if (socket_listen($sock, 5) === false) { 
     echo "socket_listen() failed: reason: " . socket_strerror(socket_last_error($sock)) . "\n"; 
    } 

    do { 
     if (($msgsock = socket_accept($sock)) === false) { 
      echo "socket_accept() failed: reason: " . socket_strerror(socket_last_error($sock)) . "\n"; 
      break; 
     } 
     /* Send instructions. */ 
     $msg = "\nWelcome to the PHP Test Server. \n" . 
      "To quit, type 'quit'. To shut down the server type 'shutdown'.\n"; 
     socket_write($msgsock, $msg, strlen($msg)); 

     do { 
      if (false === ($buf = socket_read($msgsock, 2048, PHP_NORMAL_READ))) { 
       echo "socket_read() failed: reason: " . socket_strerror(socket_last_error($msgsock)) . "\n"; 
       break 2; 
      } 
      if (!$buf = trim($buf)) { 
       continue; 
      } 
      if ($buf == 'quit') { 
       break; 
      } 
      if ($buf == 'shutdown') { 
       socket_close($msgsock); 
       break 2; 
      } 
      $talkback = "PHP: You said '$buf'.\n"; 
      socket_write($msgsock, $talkback, strlen($talkback)); 
      echo "$buf\n"; 
     } while (true); 
     socket_close($msgsock); 
    } while (true); 

    socket_close($sock); 
    ?> 

Client.php

<?php 
error_reporting(E_ALL); 

echo "<h2>TCP/IP Connection</h2>\n"; 

/* Get the port for the WWW service. */ 
$service_port = getservbyname('www', 'tcp'); 

/* Get the IP address for the target host. */ 
$address = gethostbyname('www.example.com'); 

/* Create a TCP/IP socket. */ 
$socket = socket_create(AF_INET, SOCK_STREAM, SOL_TCP); 
if ($socket === false) { 
    echo "socket_create() failed: reason: " . socket_strerror(socket_last_error()) . "\n"; 
} else { 
    echo "OK.\n"; 
} 

echo "Attempting to connect to '$address' on port '$service_port'..."; 
$result = socket_connect($socket, $address, $service_port); 
if ($result === false) { 
    echo "socket_connect() failed.\nReason: ($result) " . socket_strerror(socket_last_error($socket)) . "\n"; 
} else { 
    echo "OK.\n"; 
} 

$in = "HEAD/HTTP/1.1\r\n"; 
$in .= "Host: www.example.com\r\n"; 
$in .= "Connection: Close\r\n\r\n"; 
$out = ''; 

echo "Sending HTTP HEAD request..."; 
socket_write($socket, $in, strlen($in)); 
echo "OK.\n"; 

echo "Reading response:\n\n"; 
while ($out = socket_read($socket, 2048)) { 
    echo $out; 
} 

echo "Closing socket..."; 
socket_close($socket); 
echo "OK.\n\n"; 
?> 

Answer 1

在這兩個PHP文件創建同一端口的插座上。那就是問題所在。

服務器已經創建了Socket而客戶端必須使用Socket（沒有創造它，太）

兩個應用程序不能創建相同的插座和收聽同一端口上。

編輯： 我已經用xampp在localhost上測試了你的腳本。所以IP是127.0.0.1。服務器在端口15213上正確監聽，客戶端在此端口上正確連接。 該端口是打開的，我看到了xampp控制面板。

如果您使用腳本像你張貼在這裏，那麼你必須在Server.php

$address = 'XXX.XX.XX.XXX'; 

與

$address = '127.0.0.1'; 

和Client.php

$address = gethostbyname('www.example.com'); 

更換與

$address = gethostbyname('localhost'); 
or 
$address = '127.0.0.1';