如果某行不過去的一個過濾器

Question

我有一個查詢

SELECT id, type FROM clients WHERE 1 GROUP BY id, type 

+----+------+ 
| id | type | 
+------+----+ 
| 1 | 1 | 
| 1 | 2 | 
| 1 | 3 | 
| 2 | 2 | 
| 2 | 3 | 
+----+------+ 

可以忽略結果的組，但我想忽略ID爲「1」，因爲這有一個1型，因此，在此情況下，我只是想有id爲 「2」

誰能幫助我，謝謝

Answer 1

您可以使用NOT EXISTS：

SELECT id, type 
FROM clients AS c1 
WHERE NOT EXISTS (SELECT 1 
        FROM clients AS c2 
        WHERE c1.id = c2.id AND c2.type = 1) 

輸出：

+----+------+ 
| id | type | 
+----+------+ 
| 2 | 2 | 
| 2 | 3 | 
+----+------+ 

Answer 2

一點點不同的語法：

SELECT distinct id, type 
FROM clients 
WHERE id not in (select distinct id from clients where type=1)