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我有一個iPhone應用程序,我試圖去談談一個軌道後端。我使用NSMutableURLRequest來回拉取數據。所有的調用都可以很好地處理GET請求,但是當我需要發佈數據時,我的rails應用程序似乎無法找到會話。我已經爲get和POST請求發佈了下面的代碼。NSMutableURLRequest丟失會話信息
這是POST請求:
//Set up the URL
NSString *url_string = [NSString stringWithFormat:@"https://testserver.example.com/players.xml"];
NSURL *url = [NSURL URLWithString:url_string];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url
cachePolicy:NSURLRequestReloadIgnoringCacheData
timeoutInterval:30];
//To create an object in rails
//We have to use a post request
////This is the format when using xml
NSString *requestString = [[NSString alloc] initWithFormat:@"<player><team_game_id>%@</team_game_id><person_id>%@</person_id></player>", game, person];
NSData *requestData = [NSData dataWithBytes:[requestString UTF8String] length:[requestString length]];
[request setHTTPMethod:@"POST"];
[request setHTTPBody:requestData];
NSString *postLength = [NSString stringWithFormat:@"%d", [requestData length]];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
//For some reason rails will not take application/xml
[request setValue:@"application/xml" forHTTPHeaderField:@"content-type"];
GET請求是:
NSString *url_string = [NSString stringWithFormat:@"https://testserver.example.com/people/find_by_passport?passport=%i", passport];
passportString = [[NSMutableString alloc] initWithFormat:@"%i", passport];
NSLog(@"The passport string is %@", passportString);
NSLog(url_string, nil);
NSURL *url = [NSURL URLWithString:url_string];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url
cachePolicy:NSURLRequestReloadIgnoringCacheData
timeoutInterval:30];
我在我束手無策這裏試圖找出什麼是繼續下去,因此任何幫助,將不勝感激。
所以我有點明白我想在這裏做什麼,但我覺得我錯過了一些東西,我把Set-Cookie放到一個字符串中,存儲在一個鑰匙鏈項目中,在下一個請求中選擇它並將其添加到http標頭字段中。這就是我需要做的一切,通過「手工提取餅乾」你做了什麼? – drapergeek
非常。另請參閱編輯。 –
其實我找到了同樣的東西,我嘗試將cookie添加回頭部,但它似乎沒有幫助我。 – drapergeek