嵌套的MySQL查詢

Question

我一直在試圖爲公共交通系統編寫一個查詢，當我輸入起點和終點站號時，它將輸出路線列表。

這裏是我的MySQL表：

mysql> desc route_timings; 
+----------------+---------+------+-----+---------+----------------+ 
| Field   | Type | Null | Key | Default | Extra   | 
+----------------+---------+------+-----+---------+----------------+ 
| ID    | int(11) | NO | PRI | NULL | auto_increment | 
| route_number | int(11) | NO |  | NULL |    | 
| stop_number | int(11) | NO |  | NULL |    | 
| arrival_time | time | YES |  | NULL |    | 
| departure_time | time | YES |  | NULL |    | 
+----------------+---------+------+-----+---------+----------------+ 
5 rows in set (0.00 sec) 

下面是樣本值：

mysql> select * from route_timings; 
+----+--------------+-------------+--------------+----------------+ 
| ID | route_number | stop_number | arrival_time | departure_time | 
+----+--------------+-------------+--------------+----------------+ 
| 1 |   54 |   1 | 10:00:00  | 10:05:00  | 
| 2 |   54 |   2 | 11:00:00  | 11:05:00  | 
| 3 |   54 |   3 | 12:00:00  | 12:05:00  | 
| 4 |   55 |   3 | 13:00:00  | 13:05:00  | 
| 5 |   55 |   4 | 14:00:00  | 14:05:00  | 
| 6 |   55 |   5 | 15:00:00  | 15:05:00  | 
| 7 |   60 |   3 | 10:00:00  | 10:05:00  | 
| 8 |   60 |   2 | 11:00:00  | 11:05:00  | 
| 9 |   60 |   1 | 12:00:00  | 12:05:00  | 
+----+--------------+-------------+--------------+----------------+ 
9 rows in set (0.01 sec) 

我的問題是：如果我想列出ROUTE_NUMBER的，將包含stop_number 1和stop_number 3，我會寫類似這樣的查詢：

SELECT DISTINCT `route_number` FROM `route_timings` WHERE `route_number` IN (
    SELECT `route_number` FROM `route_timings` WHERE `stop_number`=1 
) AND `route_number` IN (
    SELECT `route_number` FROM `route_timings` WHERE `stop_number`=3 
); 

但是，上面的查詢只會返回包含兩個站點的route_number，而不是源站點（1）在目標站點（3）之前到達的路線。

查詢將返回以下：

+--------------+ 
| route_number | 
+--------------+ 
|   54 | 
|   60 | 
+--------------+ 

的ROUTE_NUMBER 60不會從1開始，到3，而是從3開始並且前往1.是否有人可以幫助我，有點添加到查詢以便查詢僅輸出其中stop_number 1的到達時間小於stop_number 3的到達時間的route_number。

在此先感謝。 -Shain

Answer 1

做了如何像重命名爲聯合收割機querys工作表約定我習慣了，但原則應該清楚

Answer 2

用途：

SELECT DISTINCT `route_number` FROM `route_timings` WHERE `stop_number` IN (1,3) 

注：爲什麼DEPARTURE_TIME爲>比ARRIVAL_TIME？

Answer 3

SELECT DISTINCT `route_number` R1 FROM R1.`route_timings` WHERE R1.`stop_number` =3 AND R1.`route_number` IN (
SELECT `route_number` R2 FROM `route_timings` WHERE R2.`stop_number`=1 AND R2.`arrival_time` > R1.`arrival_time` 
); 

我現在不能嘗試，但我希望語法是正確的。我所做的是選擇經過3的路線，然後檢查他們是否稍後停在1。這是使用SQL Server的語法和名稱

select fromStop.RouteNumber 
from routeTimings fromStop 
    inner join routeTimings toStop on toStop.RouteNumber = fromStop.RouteNumber and toStop.StopNumber = 3 and toStop.ArrivalTime > fromStop.DepartureTime 
where fromStop.StopNumber = 1 

注意調整爲：我通常使用SQLite，讓像我在SELECT route_number R2