我是java的初學者。我試圖模仿頭部第一本Java書中的單維陣列戰艦代碼。代碼沒有失敗,但我無法使其正常工作。例如:[1,2,3]
是包含戰艦位置的數組。如果我猜測除1之外的任何數字,則顯示爲未命中。但是,如果我連續三次(長度的戰列艦)猜測它是殺人的。我無法弄清楚這個問題。單維陣列戰艦編號
請問你能否幫我解決這個問題。該代碼下面貼:
package battleship;
public class battleship {
public int[] battleship = new int[3];
public int numofhits = 0;
String result = "miss";//instance variables complete
//setter method to initialize the array which holds the battle ship location
public void setbattleshiploc(int startpos) {
int i = 0;
for(i = 0; i < battleship.length; i++) {
battleship[i] = startpos + i;
System.out.println(battleship[i]);
}
System.out.println("initialized array is: " + java.util.Arrays.toString(battleship));
}
//getter method to print the set battleship array
public int[] getbattleshiploc() {
System.out.println("Battleship array is: " + battleship);
return battleship;
}
//checking whether user guess inside the battleship array location
public String guessloc(int guessnum) {
//int i = 0;
for(int cell : battleship) {
System.out.println("Guessed number is: " + guessnum + " array element: " + battleship[cell]);
System.out.println("cell: "+ cell + " ,battleship[cell]: " + battleship[cell]);
if(cell == guessnum) {
numofhits++;
if(numofhits == 3) {
result = "kill";
return result;
}//if the hits are 3 then return kill indicating that no more battle ship is available
else {
result = "hit";
return result;
}//end inner else
}//end outer if
else {
//numofhits++;
result = "miss";
return result;
}//end the if-else
}//end for loop
return "finished";
}//end function guessloc
}//end class
package battleship;
import java.util.Scanner;
public class gamelauncher {
public Scanner[] reader;
public static void main(String[] args) {
String result = "miss";
int numofguess = 0;
//int loopnum = 0;
battleship launchgame = new battleship();//launch the game
int startpos = (int) (Math.random() * 5);//generate random number between 0-4
//int[] location = {startpos, startpos + 1, startpos + 2};//initialize three consecutive array element
launchgame.setbattleshiploc(startpos);//set the array as the battleship location using setter
//display the battleship position
System.out.println("Battle shipt positions are: " + startpos +" ," + startpos+1 + " ," + startpos+2);
System.out.println("the battle ship array is: " + launchgame.getbattleshiploc());
//int[] battleshiplocation = launchgame.getbattleshiploc();
System.out.println(java.util.Arrays.toString(launchgame.getbattleshiploc()));
while(result != "kill") {
Scanner reader = new Scanner(System.in); // Reading from System.in
System.out.println("Enter a number: ");
int guess = reader.nextInt(); //get the user input integer
//reader.close();//close the scanner
//loopnum++;
numofguess++;
if(guess < 0 || guess > 7) {
System.out.println("Maximum space available is 7 units(0-6) and battleship length is 3 units, Please provide the location accordingly");
continue;
}//close if loop and go to the loop execution if the guess is not within the limits
else {
result = launchgame.guessloc(guess);
System.out.println("response from guessing method: " + result);
//get the status(hit/miss/kill) back from guess location method
if(result == "kill") {
System.out.println("We have destroyed all the parts of battle ship and it took " + numofguess +" guesses" );
break;//get out of the loop as we have destroyed everything
}//end kill
else if(result == "hit") {
System.out.println("You have destroyed " + launchgame.numofhits+" parts of batlleship, please continue");
continue;
}
else {
System.out.println("It's a miss dumbo, try again");
continue;
}
}//end outer else statement
}//end while loop
}//end main method
}//end class
當錯過一個零件時,您不應該立即返回「錯過」,只有在錯過了所有零件的情況下才應該返回它。 – Berger
如果這個例子的目標是展示如何處理數組,我會把這本書扔進垃圾箱。不要在這裏開玩笑。無論如何,不要將字符串與數字運算符(比如!=,==等)進行比較。而是使用string1.equals(string2) –