有人可以爲我分解一個PIVOT查詢嗎？

Question

我正在尋找樞紐這個數據，所以輸出可以計算每個年齡段有多少人...

以下是我所做的，但我甚至不認爲我接近... 。

我使用SQL Server 2008

SELECT  [OA_Code], Dominant_F_Age, Age_F_90plus, Age_F_85_89, Age_F_80_84, Age_F_75_79, Age_F_70_74, Age_F_65_69, Age_F_60_64, 
         Age_F_55_59, Age_F_50_54, Age_F_45_49, Age_F_40_44, Age_F_35_39, Age_F_30_34, Age_F_25_29, Age_F_20_24, Age_F_15_19, Age_F_10_14, Age_F_5_9, 
         Age_F_0_4, Age_2001_F 
FROM   cen.AgeByGenderOA 
PIVOT (
    f_Age_data 
    for [F_Age_Data] in (Age_F_90plus, Age_F_85_89, Age_F_80_84, Age_F_75_79, Age_F_70_74, Age_F_65_69, Age_F_60_64, 
         Age_F_55_59, Age_F_50_54, Age_F_45_49, Age_F_40_44, Age_F_35_39, Age_F_30_34, Age_F_25_29, Age_F_20_24, Age_F_15_19, Age_F_10_14, Age_F_5_9), 
         Age_F_0_4) 

我的表看起來像這樣：

CREATE TABLE AgeByGenderOA(
      [OA_Code] AS VARCHAR(50), 
      [Age_M_0_4] [varchar](50) NULL, 
     [Age_M_5_9] [varchar](50) NULL, 
     [Age_M_10_14] [varchar](50) NULL, 
     [Age_M_15_19] [varchar](50) NULL, 
     [Age_M_20_24] [varchar](50) NULL, 
     [Age_M_25_29] [varchar](50) NULL, 
     [Age_M_30_34] [varchar](50) NULL, 
     [Age_M_35_39] [varchar](50) NULL, 
     [Age_M_40_44] [varchar](50) NULL, 
     [Age_M_45_49] [varchar](50) NULL, 
     [Age_M_50_54] [varchar](50) NULL, 
     [Age_M_55_59] [varchar](50) NULL, 
     [Age_M_60_64] [varchar](50) NULL, 
     [Age_M_65_69] [varchar](50) NULL, 
     [Age_M_70_74] [varchar](50) NULL, 
     [Age_M_75_79] [varchar](50) NULL, 
     [Age_M_80_84] [varchar](50) NULL, 
     [Age_M_85_89] [varchar](50) NULL, 
     [Age_M_90plus] [varchar](50) NULL, 
     [Dominant_M_Age] [varchar](50) NULL, 
     [Age_2001_F] [varchar](50) NULL, 
     [Age_F_0_4] [varchar](50) NULL, 
     [Age_F_5_9] [varchar](50) NULL, 
     [Age_F_10_14] [varchar](50) NULL, 
     [Age_F_15_19] [varchar](50) NULL, 
     [Age_F_20_24] [varchar](50) NULL, 
     [Age_F_25_29] [varchar](50) NULL, 
     [Age_F_30_34] [varchar](50) NULL, 
     [Age_F_35_39] [varchar](50) NULL, 
     [Age_F_40_44] [varchar](50) NULL, 
     [Age_F_45_49] [varchar](50) NULL, 
     [Age_F_50_54] [varchar](50) NULL, 
     [Age_F_55_59] [varchar](50) NULL, 
     [Age_F_60_64] [varchar](50) NULL, 
     [Age_F_65_69] [varchar](50) NULL, 
     [Age_F_70_74] [varchar](50) NULL, 
     [Age_F_75_79] [varchar](50) NULL, 
     [Age_F_80_84] [varchar](50) NULL, 
     [Age_F_85_89] [varchar](50) NULL, 
     [Age_F_90plus] [varchar](50) NULL, 
     [Dominant_F_Age] [varchar](50) NULL, 
     [MAPINFO_ID] [varchar](50) NULL) 

正如你可以看到它是一個巨大的表。 「Age_M_0_4」列填充了數字。

，我想我的輸出讀

OA_Code, Age, countOfAge 
123456, Age_0_4, 26 
123456, Age_5_9, 24 
789456, Age_0_4, 10 
789456, Age_5_9, 12 

這將是包容性的男性和女性的青睞。

任何人都喜歡在這一個裂縫？

最後：包含在「Age_M_」列中的數據都是數字計數。 50，40，2，0等...

Answer 1

你不想要一個PIVOT，你需要UNPIVOT數據。由於您使用的是SQL Server 2008+，因此可以使用CROSS APPLY和VALUES子句。該代碼將與此類似：

select t.OA_Code, 
    c.age, 
    sum(cast(c.value as int)) countOfAge 
from AgeByGenderOA t 
cross apply 
(
    values 
    ('Age_0_4', Age_M_0_4), 
    ('Age_5_9', Age_M_5_9), 
    ('Age_10_14', Age_M_10_14), 
    ('Age_15_19', Age_M_15_19) ... add the other columns here 
) c (age, value) 
group by t.OA_Code, c.age 

見SQL Fiddle with Demo

編輯，如果你想同時男/女列，你將包括所有的值子句中的列，而是給他們同樣的年齡範圍值：

select t.OA_Code, 
    c.age, 
    sum(cast(c.value as int)) countOfAge 
from AgeByGenderOA t 
cross apply 
(
    values 
    ('Age_0_4', Age_M_0_4), 
    ('Age_5_9', Age_M_5_9), 
    ('Age_10_14', Age_M_10_14), 
    ('Age_15_19', Age_M_15_19), 
    ('Age_0_4', Age_F_0_4), 
    ('Age_5_9', Age_F_5_9), 
    ('Age_10_14', Age_F_10_14), 
    ('Age_15_19', Age_F_15_19) 
) c (age, value) 
group by t.OA_Code, c.age; 

見SQL Fiddle with Demo