,但在這裏它是: -創建可重用的方法使用,我不知道這個問題的標題仿製藥
我有我的代碼: -
HttpClient client = new HttpClient();// Create a HttpClient
client.BaseAddress = new Uri("http://localhost:8081/api/Animals");//Set the Base Address
//eg:- methodToInvoke='GetAmimals'
//e.g:- input='Animal' class
HttpResponseMessage response = client.GetAsync('GetAllAnimals').Result; // Blocking call!
if (response.IsSuccessStatusCode)
{
XmlSerializer serializer = new XmlSerializer(typeof(Animal));//Animal is my Class (e.g)
string data = response.Content.ReadAsStringAsync().Result;
using (MemoryStream ms = new MemoryStream(UTF8Encoding.UTF8.GetBytes(data)))
{
var _response = (Animal)serializer.Deserialize(ms);
return _response;
}
}
這工作得很好,現在如果我需要做的另一大類同說Dog
或Cat
什麼我做的是: -
HttpClient client = new HttpClient();// Create a HttpClient
client.BaseAddress = new Uri("http://localhost:8081/api/Animals");//Set the Base Address
//eg:- methodToInvoke='GetAmimals'
//e.g:- input='Animal' class
HttpResponseMessage response = client.GetAsync('GetAllDogs').Result; // Blocking call!
if (response.IsSuccessStatusCode)
{
XmlSerializer serializer = new XmlSerializer(typeof(Dog));//Animal is my Class (e.g)
string data = response.Content.ReadAsStringAsync().Result;
using (MemoryStream ms = new MemoryStream(UTF8Encoding.UTF8.GetBytes(data)))
{
var _response = (Dog)serializer.Deserialize(ms);
return _response;
}
}
現在,我想這將其更改爲通用類,像下面這樣: -
private T GetAPIData(T input,string parameters, string methodToInvoke)
{
try
{
HttpClient client = new HttpClient();
client.BaseAddress = new Uri("http://localhost:8081/api/Animals");
//eg:- methodToInvoke='GetAmimals'
//e.g:- input='Animal' class
HttpResponseMessage response = client.GetAsync(methodToInvoke).Result; // Blocking call!
if (response.IsSuccessStatusCode)
{
XmlSerializer serializer = new XmlSerializer(typeof(input));
string data = response.Content.ReadAsStringAsync().Result;
using (MemoryStream ms = new MemoryStream(UTF8Encoding.UTF8.GetBytes(data)))
{
var _response = (input)serializer.Deserialize(ms);
return _response;
}
}
}
catch (Exception ex)
{
throw new Exception(ex.Message);
}
return (T)input;
}
但是,我不能做到這一點。我甚至不知道怎麼稱呼這種方法?
var testData = GetAPIData(new Aminal(),null,'GetAmimals');
這是否會工作...這是我第一次使用泛型。
: - 謝謝!A萬噸... +1提'Usage',它給了一個清晰的畫面。 – Shubh