SQL（需要打印的所有重複的值ID）

Question

Empid----Name 
    1  aa 
    2  bb 
    3  cc 
    4  aa 
    5  bb 

我需要輸出到打印爲其重複名稱

output Required: 
1,2,4,5. 

Answer 1

試試這個

select empid from table 
where name in (select name from table group by name having count(*)>1) 

Answer 2

試試這個EMPID號碼。

  select distinct t.Empid from 
     #Your_Table t inner join 
     (
      select Name, COUNT (Name) as count 
      from #Your_Table 
      group by Name 
      having COUNT (Name) > 1 
     )a on a.Name=t.Name 

     order by t.Empid 

Answer 3

如果您使用的是sql server，請使用下面的腳本。

;WITH CTE_1 AS 
(
SELECT *,COUNT(1)OVER(PARTITION BY Name ORDER BY Name) CNT 
FROM [YourTable] 
) 
SELECT ID 
FROM [CTE_1] 
WHERE CNT > 1 

Answer 4

SELECT * 
FROM table AS parent 
WHERE EXISTS(
SELECT * 
FROM table AS sub 
WHERE sub.Name == parent.Name && parent.Empid <> sub.Empid 
) 

Answer 5

SELECT * FROM (
     SELECT ROW_NUMBER() OVER (PARTITION BY Name ORDER BY Name) RowNo,* 
     From Your_Table 
    ) a 
    WHERE RowNo > 1