SQL子查詢：不返回行

Question

我掙扎在SQL查詢過濾條目...我有三個表：

1）工作

2）paper1

3）paper2

paper1和paper2有一個列表job_id其中引用了相應的作業ID;所以具有編號的工作具有paper1.job_id的。

現在，我希望看到有相應的paper1但沒有paper2所有作業（這樣的：未完成的，因爲paper1和paper2是這個職位的要求得到滿足）。我的嘗試是這樣的，但它沒有正確工作：

SELECT id 
FROM jobs 
WHERE (SELECT id FROM paper1 WHERE (job_id = jobs.id) != 0 LIMIT 1) 
AND (SELECT id FROM paper2 WHERE (job_id = jobs.id) = NULL LIMIT 1) 

任何幫助表示讚賞;謝謝。

Answer 1

嘗試作業：

Select job_id 
FROM paper1 
WHERE job_id NOT IN (Select job_id from paper2 group by paper2) 

GROUP BY job_id; 

Answer 2

select id 
from jobs 
where exists (select p1.id from paper1 as p1 where p1.job_id = jobs.id) 
    and not exists (select p2.id from paper2 as p2 where p2.job_id = jobs.id) 

Answer 3

根據我的理解，我認爲你只想要其中僅在paper1但不是在paper2 如果多數民衆贊成的要求，然後嘗試下面的代碼

select * from jobs where id in (select distinct j1 from 
(select a.job_id as j1,b.job_id as j2 from paper1 a,paper2 b where a.job_id=b.job_id(+)) 
where j2 is null)