從網頁提取內容並在TextView中顯示

我想用某些關於某事的信息更新用戶。我想我會從網頁獲取一些信息並在TextView中顯示。我已經寫了一些代碼，但它目前給這樣的輸出TextView從網頁提取內容並在TextView中顯示

<html> 
<head> 
</head> 
<body> 
This is the test message for our user. 
</body> 
</html>

但我想，該消息應該只包含這一行，沒有別的。

This is the test message for our user.

我寫的代碼是：

public class MainActivity extends Activity { 

private Button btnSkipContinue; 
private TextView txtMessage; 
private StringBuilder response; 
private String text; 

@Override 
public void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    this.requestWindowFeature(Window.FEATURE_NO_TITLE); 
    setContentView(R.layout.activity_main); 
    btnSkipContinue = (Button) findViewById(R.id.btnSkipCon); 
    txtMessage = (TextView) findViewById(R.id.txtMsgForUsers); 
    btnSkipContinue.setOnClickListener(new OnClickListener() { 
     public void onClick(View arg0) { 
      finish(); 
      Intent intent = new Intent(MainActivity.this, SecondActivity.class); 
      startActivity(intent); 
     } 
    }); 

    try { 
     URLConnection connection = new URL("http://mywebiste.com/msg/MsgForUsers.html").openConnection(); 
     connection.setRequestProperty("Accept-Charset", "UTF-8"); 
     InputStream responseStream = connection.getInputStream(); 
     BufferedReader br = new BufferedReader(new InputStreamReader(responseStream)); 
     response = new StringBuilder(); 
     String line; 
     while ((line = br.readLine()) != null) { 
      response.append(line); 
     } 
     text = response.toString(); 
     Log.i("Output", text); 
    } catch (MalformedURLException e) { 
     e.printStackTrace(); 
    } catch (IOException e) { 
     e.printStackTrace(); 
    } 
    txtMessage.setText(text); 
} 
}

來源

2012-11-08 Tapan Desai

使用Html.fromHtml() ..

String htmlString = "<html><head></head><body>This is the test message for our user.</body></html>"; 
textView.setText(Html.fromHtml(htmlString));

來源

2012-11-08 07:53:13 Nermeen

BINGO ..我得到了想要的輸出感謝 –

考慮接受的答案，如果它解決了你的問題:) – juned

從網頁提取內容並在TextView中顯示

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