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我想從方法中的顏色改變4個按鈕,但是即使我按下其他按鈕之一,計數器也會繼續,並且我希望每個按鈕都會計算出它自身,並從0開始而不是從另一個位置開始按鈕已停止。如何在方法中改變按鈕的顏色?
int count = 0;
public void ColourChange(JButton jButtonColour1){
//Changes the colours of the buttons, doesn't work good because it goes on counting for the other buttons too.
//returns the counter to 0 after it gets to 10.
if (count >= 10) {
count = 0;
}
count++;
//Makes sure it can be used at all the 4 buttons instead on just 1.
JButton setColour = jButtonColour1, jButtonColour2, jButtonColour3, jButtonColour4;
Color color;
switch (count) {
case 1:
count = 1;
setColour.setBackground(Color.BLACK);
break;
case 2:
count = 2;
setColour.setBackground(Color.RED);
break;
case 3:
count = 3;
setColour.setBackground(Color.PINK);
break;
case 4:
count = 4;
setColour.setBackground(Color.GREEN);
break;
case 5:
count = 5;
setColour.setBackground(Color.BLUE);
break;
case 6:
count = 6;
setColour.setBackground(Color.YELLOW);
break;
case 7:
count = 7;
setColour.setBackground(Color.MAGENTA);
break;
case 8:
count = 8;
setColour.setBackground(Color.cyan);
break;
case 9:
count = 9;
setColour.setBackground(Color.GRAY);
break;
case 10:
count = 10;
setColour.setBackground(Color.ORANGE);
break;
}
}
你是什麼意思 「每個櫃檯」?代碼中只有一個計數器變量。如果你想爲每個按鈕都有一個按鈕,則需要爲每個按鈕聲明一個按鈕。 –
你想通過點擊來改變你的按鈕顏色嗎? – Russiancold
count = 1,count = 2等在交換機中是沒有意義的。想想爲什麼。 – Russiancold