2016-07-18 47 views
1

我有一個具有重複名稱的向量,我想將其轉換爲數據框,每個重複名稱都是單個列。我有一個解決方案,但肯定R提供了一個更乾淨的方式?R將具有重複名稱的命名向量轉換爲數據框

#Example Input: x 
x <- c(1,2,3,4,3,5,6,7) 
names(x) <- c("a","b","a","b","a","b","a","b") 

#Desired Output: x.desired 
x.desired <- data.frame(matrix(nrow=4,ncol=2)) 
names(x.desired) <- c("a","b") 
x.desired$a <- c(1, 3, 3, 6) 
x.desired$b <- c(2, 4, 5, 7) 

#Using data frame cast (doesn't work) 
x.wrong <- data.frame(x) 

#My solution, surely there is a cleaner way? I.e. a one line solution 
colNames <- unique(names(x)) 
x.correct <- data.frame(matrix(nrow=length(x)/length(colNames), ncol=length(colNames))) 
names(x.correct) <- colNames 
for (i in 1:length(colNames)) 
    x.correct[,colNames[i]] <- x[which(names(x) == colNames[i])] 

回答

1

我們可以splitnameslistcbind

do.call(cbind, split(x, names(x))) 

或者使用data.frame

data.frame(split(x, names(x))) 
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