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我目前正在進行工資發放。我已經設法在同一天計算出入職和退休員工的小時數。以下是我正在提取的記錄的樣本表。我的問題是,如果員工在晚上10點到早上6點的班次或類似的班次工作,要求他們在第二天工作,我無法弄清楚使用什麼條件。 Im在我的查詢中使用distinct,因爲hr提供的數據包含許多重複條目。從特定日期獲得記錄
----------------------------------------------------
| empID | Date | Type | RecTime |
----------------------------------------------------
| 1 | 2012-11-01 | 1-TIME IN | 21:45 |
| 1 | 2012-11-02 | 1-TIME OUT | 06:05 |
| 1 | 2012-11-02 | 1-TIME IN | 21:33 |
| 1 | 2012-11-03 | 1-TIME OUT | 06:08 |
| 1 | 2012-11-04 | 1-TIME IN | 11:49 |
| 1 | 2012-11-04 | 1-TIME OUT | 21:39 |
| 1 | 2012-11-05 | 1-TIME IN | 14:25 |
| 1 | 2012-11-05 | 1-TIME OUT | 20:07 |
----------------------------------------------------
這是我的PHP代碼:
<?php
$c = 1;
$query = mysql_query("SELECT DISTINCT EmpID, Date, Type from paymaster2c.tx_tito_pm ORDER BY EmpID, Date");
while ($row = mysql_fetch_array($query)){
$EID = $row['EmpID'];
$D = $row['Date'];
$T = $row['Type'];
$RTi = 'no time in';
$RTo = 'no time out';
$RBo = 'no break out';
$RBi = 'no break in';
$query1 = mysql_query("SELECT RecTime from tx_tito_pm WHERE Date='$D' AND EmpID='$EID' AND Type='1-TIME IN' LIMIT 1");
while ($row1 = mysql_fetch_array($query1)){
$RTi = date('H:i:s',strtotime($row1['RecTime']));
if (date('H:i:s',strtotime('$RTi')) > date('H:i:s',strtotime('03:00 PM')) && date('H:i:s',strtotime('$RTi')) <= date('H:i:s',strtotime('11:59 PM'))) {
$date = new DateTime('$D');
$date->add(new DateInterval('P1D'));
$NewDate = $date->format('Y-m-d');
//$NewD = date('Y-m-d', strtotime('$D + 1day'));
$query3 = mysql_query("SELECT RecTime from tx_tito_pm WHERE Date='$date' AND EmpID='$EID' AND Type='4-TIME OUT' LIMIT 1");
while ($row3 = mysql_fetch_array($query3)){
$RTo = date('H:i:s',strtotime($row3['RecTime']));
$RTii = date('H:i:s',strtotime('23:59:00')) - date('H:i:s',strtotime($RTi));
$start_date = new DateTime(date('H:i:s',strtotime('23:59:00')));
$since_start = $start_date->diff(new DateTime(date('H:i:s',strtotime('$RTi'))));
$start_date1 = new DateTime(date('H:i:s',strtotime('00:00:00')));
$since_start1 = $start_date1->diff(new DateTime(date('H:i:s',strtotime('$RTo'))));
$M1 = $since_start1->i ;
$H1 = $since_start1->h ;
$M = $since_start->i ;
$H = $since_start->h ;
$a = $H + $H1;
$b = $M + $M1;
$RTD = $RTo-$RTi;
echo "#" .$c. " ". $EID . " == " . $D . " == " . date('D', strtotime($D)) ." == " . $T ." ==>>" .$RTo. "-". $RTi. "==" .$RTD. "//" .$a. "hrs and " .$b. "minutes. <br /> \n";
$c++;
}
}
else {
$query2 = mysql_query("SELECT RecTime from tx_tito_pm WHERE Date='$D' AND EmpID='$EID' AND Type='4-TIME OUT' LIMIT 1");
while ($row2 = mysql_fetch_array($query2)){
$RTo = date('H:i:s',strtotime($row2['RecTime']));
$start_date = new DateTime(date('H:i:s',strtotime($RTo)));
$since_start = $start_date->diff(new DateTime(date('H:i:s',strtotime($RTi))));
$M = $since_start->i ;
$H = $since_start->h ;
$RTD = $RTo-$RTi;
echo "#" .$c. " ". $EID . " == " . $D . " == " . date('D', strtotime($D)) ." == " . $T ." ==>>" .$RTo. "-". $RTi. "==" .$RTD. "//" .$H. "hrs and " .$M. "minutes. <br /> \n";
$c++;
}
}
}
}
echo $c;
?>
希望有人能幫助我。非常感謝你提前。
請不要使用'mysql_ *',它已經過時並且不安全。閱讀關於PDO和MySQLi。 –
您需要維護表級別的額外信息。需要保持每個員工工作的轉變,每個班次的開始和結束時間。您不應該使用DISTINCT,因爲員工可能會在班次中多次進入和退出。有了這些信息,你應該能夠滿足要求。 – rags
@FranciscoPresencia,我現在還在嘗試學習PDO和MySQLi。仍然在學習,但是,儘管如此。:) – user2842120