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我已經顯示的HTML表格,表格中管理員查看用戶信息。我創建了一個鏈接/圖標來刪除特定用戶(行),但我收到500內部服務器錯誤。刪除SQL行與jQuery/Ajax和PHP
他們是這裏的另一個類似的問題這讓我很遠,但我仍收到錯誤
我的表:
$query = "SELECT zone, firstname, lastname, email, business, reg_date, phone FROM UserList";
// Display users is a table format
$result = $conn->query($query);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<tr><td> " . $row["zone"]. "</td><td> " . $row["firstname"]. "</td><td> " . $row["lastname"] . "</td><td> " . $row["email"]. "</td><td> " . $row["business"]. "</td><td> " . $row["reg_date"]. " <a class='deleteRow' id='.$row->id.' href=''><i class='fa fa-times' aria-hidden='true'></a></td></i></tr><br> ";
}
} else {
echo "<div class='no_results'>No Users Added</div>";
}
我的jQuery/AJAX:
$(function(){
$(document).on('click','.deleteRow',function(){
var del_id= $(this).attr('id');
var $ele = $(this).parent().parent();
$.ajax({
type:'POST',
url:'removeUser.php',
data:{'del_id':del_id},
success: function(data){
if(data=="YES"){
$ele.fadeOut().remove();
}else{
alert("can't delete the row")
}
}
});
});
});
我removeUser文件:
<?php
include('config.php');
$user_id = $_POST['del_id'];
//echo $user_id
$qry = "DELETE FROM UserList WHERE id = '$user_id'";
$result = mysql_query($qry);
if(isset($result)) {
echo "YES";
} else {
echo "NO";
}
?>
爲什麼我得到一個500內部服務器錯誤,如何解決?謝謝。
你的代碼是脆弱的[** SQL注入**](https://en.wikipedia.org/wiki/SQL_injection)攻擊。你應該使用[** mysqli **](https://secure.php.net/manual/en/mysqli.prepare.php)或[** PDO **](https://secure.php.net/ manual/en/pdo.prepared-statements.php)準備帶有綁定參數的語句,如[**這篇文章**]所述(https://stackoverflow.com/questions/60174/how-can-i-prevent-sql步噴射功能於PHP)。 –
不要使用'mysql_ *'功能。自v5.5(2013年6月)開始,它們已被棄用,並從v7.0(2015年12月)開始刪除。請使用[** mysqli _ ***](https://secure.php.net/manual/en/book.mysqli.php)或[** PDO **](https://secure.php.net /manual/en/book.pdo.php)與[**準備語句**](https://secure.php.net/manual/en/pdo.prepare.php)和[**綁定參數** ](https://secure.php.net/manual/en/pdostatement.bindparam.php)。 –
知道了謝謝! – DLzer