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我有以下加入語句:SQL加入,消除重複的結果
SELECT DISTINCT dn.fname, dn.lname,w.websit,q.qual,q.year,q.postqual,p.pnumber,a.accred,n.nspecial
FROM cur_doctor_names dn
LEFT JOIN cur_website w ON dn.userid = w.userid
LEFT JOIN cur_qualification q ON dn.userid = q.userid
LEFT JOIN (Select * from cur_phone_numbers where type="primary") p On dn.userid = p.userid
Left JOIN cur_accreditation a On dn.userid = a.userid
Left JOIN cur_niche n On dn.userid = n.userid
WHERE dn.userid =69
GROUP BY p.pnumber
對於表cur_phone_numbers(P),cur_accreditation(一),cur_niche(n)的結果可以從0到3記錄一個包含用戶,我目前得到的結果給了我所有可能的數據組合。我試着在列上單獨使用group by,但是這消除了其他列的結果。我不介意用空值得到結果。這是我目前得到的結果是:
fname lname website qual year postqual pnumber accred nspecial
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First Doctor Last Doctor NULL NULL NULL NULL 123 ISO 9001 one
First Doctor Last Doctor NULL NULL NULL NULL 123 ISO 9001 two
First Doctor Last Doctor NULL NULL NULL NULL 123 ISO one
First Doctor Last Doctor NULL NULL NULL NULL 123 ISO two
First Doctor Last Doctor NULL NULL NULL NULL 1234 ISO 9001 one
First Doctor Last Doctor NULL NULL NULL NULL 1234 ISO 9001 two
First Doctor Last Doctor NULL NULL NULL NULL 1234 ISO one
First Doctor Last Doctor NULL NULL NULL NULL 1234 ISO two
根據您所提供的數據,它不重複的數據。最後3列'pnumber','accred','nspecial'顯示每行不同的值。如果你只想要一個值,那麼你需要決定你想要返回哪一個。 – Taryn