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我想從兩個不同表(TABLE_A和TABLE_B)中選擇行。我使用的是oracle db和hibernate。這裏是我的表:SQL從具有不同列名的兩個不同表中選擇行
下面是TABLE_A
+----+--------+---------+-----------+---------------------+---------------------+
| ID | AMOUNT | BALANCE | STATUS | CREATE_DATE | END_DATE |
+----+--------+---------+-----------+---------------------+---------------------+
| 1 | 5 | 5 | FINISHED | 2014-02-27 15:10:20 | 2014-02-27 15:10:20 |
| 2 | 12 | 17 | TIMED_OUT | 2014-02-27 15:10:20 | 2014-02-27 15:10:20 |
| 3 | 21 | 38 | COMMITED | 2014-02-27 15:10:20 | 2014-02-27 15:10:20 |
+----+--------+---------+-----------+---------------------+---------------------+
下面是TABLE_B
+----+----------------+---------------+----------------+---------------------+
| ID | PAYMENT_AMOUNT | TOTAL_BALANCE | PAYMENT_STATUS | REQUEST_TIMESTAMP |
+----+----------------+---------------+----------------+---------------------+
| 1 | 3 | 23 | FAILED | 2014-02-27 15:10:20 |
| 2 | 12 | 11 | FULFILLED | 2014-02-27 15:10:20 |
| 3 | 2 | 9 | TIMED_OUT | 2014-02-27 15:10:20 |
+----+----------------+---------------+----------------+---------------------+
我想要做的是,我需要得到像單個查詢以下結果:
+--------+---------+-----------+---------------------+---------------------+
| AMOUNT | BALANCE | STATUS | DATE | END_DATE |
+--------+---------+-----------+---------------------+---------------------+
| 5 | 5 | FINISHED | 2014-02-27 15:10:20 | 2014-02-27 15:10:20 |
| 12 | 17 | TIMED_OUT | 2014-02-27 15:10:20 | 2014-02-27 15:10:20 |
| 21 | 38 | COMMITED | 2014-02-27 15:10:20 | 2014-02-27 15:10:20 |
| 3 | 23 | FAILED | 2014-02-27 15:10:20 | null |
| 12 | 11 | FULFILLED | 2014-02-27 15:10:20 | null |
| 2 | 9 | TIMED_OUT | 2014-02-27 15:10:20 | null |
+--------+---------+-----------+---------------------+---------------------+
的結果是ordered by DATE
。列的說明如下:
AMOUNT = TABLE_A.AMOUNT or TABLE_B.PAYMENT_AMOUNT
BALANCE = TABLE_A.BALANCe or TABLE_B.TOTAL_BALANCE
STATUS = TABLE_A.STATUS or TABLE_B.PAYMENT_STATUS
DATE = TABLE_A.CREATE_DATE or TABLE_B.REQUEST_TIMESTAMP
END_DATE = TABLE_A.END_DATE or null
有沒有什麼辦法讓這些類型的Oracle數據庫中,並結合這些結果以Java中的Hibernate對象的任何方式的結果呢?
謝謝,我發現'UNION ALL'和它的工作對我來說:) – sedran