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我想要建立一個簡單的電話本的Web應用程序，以幫助我學習的角度，我堅持了這個錯誤的特性「推」 - 無法讀取未定義的錯誤的特性「推」。 任何人都可以指出有什麼不對？AngularJS無法讀取未定義的錯誤
是目標變量，否則我試圖把源的錯誤？
JS：
(function() {
var app = angular.module('PhonebookApp', []);
app.controller('BookController', function() {
this.contacts = [{
firstName: "Contact1",
lastName: "LastName1",
phone: 123123123123,
notes: "None"
}];
});
app.controller('ContactController', function() {
//this.contact = {};
this.contact = {
firstName: "Tim2",
lastName: "Last2",
phone: 12312312312,
notes: "notessss"
};
this.addContact = function(contacts) {
contacts.push(this.contact);
};
});
})();HTML：
<section ng-controller="BookController as bookCtrl">
<table>
<tr>
<td>First Name</td>
<td>Last Name</td>
<td>Phone Number</td>
<td>Notes</td>
</tr>
<tr ng-repeat="contact in bookCtrl.contacts">
<td>{{ contact.firstName }}</td>
<td>{{ contact.lastName }}</td>
<td>{{ contact.phone }}</td>
<td>{{ contact.notes }}</td>
</tr>
</table>
</section>
<section>
<div class="form_addContact">
<form ng-show="showForm" ng-controller="ContactController as contactCtrl" ng-submit="contactCtrl.addContact(bookCtrl.contacts)" novalidate>
<label>
First Name:
<input type="text" required ng-pattern="/^(\D)+$/" ng-model="contactCtrl.contact.firstName"></input>
<p class="inputErr" ng-show="contactCtrl.contact.firstName.$error.pattern">First name must contain letters only!</p>
</label>
<label>
Last Name:
<input type="text" ng-pattern="/^(\D)+$/" ng-model="contactCtrl.contact.lastName"></input>
<p class="inputErr" ng-show="contactCtrl.contact.lastName.$error.pattern">Last name must contain letters only!</p>
</label>
<label>
Phone Number:
<input type="number" required ng-model="contactCtrl.contact.phone"></input>
</label>
<label>
Notes:
<input type="text" ng-model="contactCtrl.contact.notes"></input>
</label>
<input type="submit" value="Submit" />
</form>
這是因爲你在另一個控制器定義你的變量'bookCtrl.contacts' – messerbill