在T-SQL 2日期間工作日

Question

我有兩個日期，想知道有多少個工作日（週一至週五），有

例如歸來數

thu jan 1 20xx  
fri jan 2 20xx  
sat jan 3 20xx  
sun jan 4 20xx  
mon jan 5 20xx 

1月1日，1月5日將返回3

（可以忽略公衆假期）

Answer 1

嘗試

DateDiff(day, @DtA, @DtB) - 2 * DateDiff(Week, @DtA, @DtB) 

這可能不完全正常工作，但可以看到的想法。稍作修改即可使用。

Answer 2

試試這個：

SET DATEFIRST 1 
DECLARE @StartDate datetime 
     ,@EndDate datetime 
SELECT @StartDate='6/21/2011' 
     ,@EndDate='6/28/2011' 
;with AllDates AS 
(
    SELECT @StartDate AS DateOf, datepart(weekday,getdate()) AS WeekDayNumber 
    UNION ALL 
    SELECT DateOf+1, datepart(weekday,DateOf+1) 
     FROM AllDates 
    WHERE DateOf<@EndDate 
) 
SELECT COUNT(*) AS WeekDayCount FROM AllDates WHERE WeekDayNumber<=5 

OUTPUT：

WeekDayCount 
------------ 
6 

(1 row(s) affected) 

如果你有一個假期表，可以參與進來，並刪除那些爲好。

編輯基於@Ross沃森評論：

SET DATEFIRST 1 
DECLARE @StartDate datetime 
     ,@EndDate datetime 
SELECT @StartDate='6/21/2011' 
     ,@EndDate='6/28/2011' 
;with AllDates AS 
(
    SELECT @StartDate AS DateOf, datepart(weekday,getdate()) AS WeekDayNumber 
    UNION ALL 
    SELECT DateOf+1, (WeekDayNumber+1) % 7 
     FROM AllDates 
    WHERE DateOf<@EndDate 
) 
SELECT COUNT(*) AS WeekDayCount FROM AllDates WHERE WeekDayNumber>0 AND WeekDayNumber<6 
--I don't like using "BETWEEN", ">", ">=", "<", and "<=" are more explicit in defining end points 

產生相同的輸出原始查詢。

Answer 3

嘗試以下操作：

DECLARE @StartDate DATETIME 
DECLARE @EndDate DATETIME 
SET @StartDate = '2011/06/01' 
SET @EndDate = '2011/06/31' 

SELECT 
    (DATEDIFF(dd, @StartDate, @EndDate) + 1) - 
    (DATEDIFF(wk, @StartDate, @EndDate) * 5) - 
    (
     CASE 
      WHEN DATENAME(dw, @StartDate) in 
       ('Sunday', 'Tuesday', 'Wednesday', 'Turesday', 'Saturday') 
      THEN 1 
      ELSE 0 
     END 
    ) - 
    (
     CASE 
      WHEN DATENAME(dw, @EndDate) in 
       ('Sunday', 'Tuesday', 'Wednesday', 'Turesday', 'Saturday') 
      THEN 1 
      ELSE 0 
     END 
    ) 

Answer 4

假設日期不能超過五個年半彼此（或使用master..spt_values自己tally table代替）：

DECLARE @date1 datetime, @date2 datetime; 
SET @date1 = '20110901'; 
SET @date2 = '20110905'; 

SELECT COUNT(*) 
FROM (
    SELECT 
    Date = DATEADD(day, number, @date1) 
    FROM master..spt_values 
    WHERE type = 'P' 
    AND number between 0 AND DATEDIFF(day, @date1, @date2) 
) s 
WHERE DATENAME(DW, Date) NOT IN ('Saturday', 'Sunday') 

Answer 5

另請參閱這是否有幫助 http://blog.sqlauthority.com/2007/06/08/sql-server-udf-function-to-display-current-week-date-and-day-weekly-calendar/

Answer 6

由於遞歸，此方法受限於約100天。這適用於我測試過的日期範圍。同樣的想法，刪除了數學和簡化：

BEGIN 
    SET DATEFIRST 1 
    DECLARE @StartDate datetime 
      ,@EndDate datetime 
    SELECT @StartDate='12/16/2015' 
      ,@EndDate='1/8/2016' 
    ;with AllDates AS 
    (
     SELECT @StartDate AS DateOf 
     UNION ALL 
     SELECT DateOf+1 
      FROM AllDates 
     WHERE DateOf<@EndDate 
    ) 
    SELECT COUNT(*) AS WeekDayCount 
     FROM 
     AllDates 
    WHERE 
     datepart(weekday,DateOf) between 1 AND 5 

    --SELECT DateOf [date], datepart(weekday,DateOf) [day] 
    --FROM 
    -- AllDates 
    --WHERE 
    -- datepart(weekday,DateOf) between 1 AND 5 
END