2013-10-24 46 views
0

我有一個製表符分隔的CSV,需要將每行分割爲不同的CSV,文件名爲[FirstName] [LastName] .csv。PowerShell:將每行CSV導出到單個文件

此外,我需要操縱一些數據,特別是從SSN中刪除破折號。

樣本含量

FirstName LastName SSN 
========= ========= ====== 
Albert  Abernathy 111-11-1111 
Billy  Barty  222-22-2222 
Chris  Canton  333-33-3333 

所需的輸出(文件名| CSV內容)

Albert Abernathy.csv | Albert  Abernathy 111111111 
Billy Barty.csv  | Billy  Barty  222222222 
Chris Canton.csv  | Chris  Canton  333333333 

這裏是我到目前爲止所。

$csvFile = "C:\Test\List.csv" 
$folderPath = Split-Path -Parent $csvFile 
$csv = Import-Csv -Path $csvFile -Delimiter "`t" 
| Where-Object {$_.LastName -ne ""} ##Prevent importing blank lines 
| Foreach-Object {$_.SSN -Replace "-","" } ##Remove dashes from SSN 
foreach ($line in $csv) 
{ $saveName = $line.FirstName + " " + $line.LastName + ".csv" 
    Export-Csv -Delimiter "`t" -Path $folderPath\$saveName 
} 

到目前爲止,所有這些都在運行,但它只是在最後一個條款之後暫停而沒有任何反應。正如我拼湊在一起,這從谷歌搜索,我敢肯定,我的語法需要工作,所以我會很感激,如果有人能在正確的方向

--Update--

信用點我alroc將我指向正確的方向,mjolinor提供了無法在其他地方找到的無價REPLACE語法。這是我的最後腳本。

$csvFile = "C:\Test\List.csv" 
$folderPath = Split-Path -Parent $csvFile 

### filter out blank records and delete dashes from SSN ### 
(Get-Content $csvFile | 
    Select-Object | 
    Where-Object {$_.LastName -ne ""}) | #Rows with non-blank last name 
    Foreach-Object {$_ -Replace '(\d{3})-(\d{2})-(\d{4})','$1$2$3'} | 
    Set-Content $csvFile 

### import csv data and export file for each row ### 
$csv = Import-Csv -Path $csvFile -Delimiter "`t" 
foreach ($row in $csv) { 
    $outPath = Join-Path -Path $folderPath -ChildPath $($row.FirstName + " " + $row.LastName + ".csv"); 
    $row | Select-Object | 
     ConvertTo-Csv -NoTypeInformation -Delimiter "`t" | 
     Foreach-Object {$_.Replace('"','')} | #Delete quotes around each "cell" 
     Out-File $outPath 
    (Get-Content $outPath | 
     Select-Object -Skip 1) | #Delete header 
     Set-Content $outPath 
} 

回答

1

我不是你所說的「最後的條款後,只是停頓了一下,什麼也沒發生」,但它可能是與你的管路import-csv你的過程的其餘部分,並試圖指派清楚什麼結果輸入$csv。這個工作對我來說:

$csvFile = "C:\Test\List.csv" 
$folderPath = Split-Path -Parent $csvFile 
$csv = Import-Csv -Path $csvFile -Delimiter "`t" 
foreach ($record in $csv) { 
    $OutFileName = join-path -Path $folderPath -ChildPath $($record.FirstName + " " + $record.LastName + ".csv"); 
    $record|select-object FirstName,LastName,@{name="SSN";expression={$_.SSN -replace "-",""}}|export-csv -NoTypeInformation -Path $OutFileName -Delimiter "`t"; 
} 

或者,如果你想這樣做,沒有中間變量,保持更多的管道-Y:

$csvFile = "C:\Test\List.csv" 
$folderPath = Split-Path -Parent $csvFile 
Import-Csv -Path $csvFile -Delimiter "`t" | foreach { 
    $OutFileName = join-path -Path $folderPath -ChildPath $($_.FirstName + " " + $_.LastName + "2.csv"); 
    $_|select-object FirstName,LastName,@{name="SSN";expression={$_.SSN -replace "-",""}}|export-csv -NoTypeInformation -Path $OutFileName -Delimiter "`t"; 
} 
+0

這兩個工作如廣告。任何避免在輸出中指定每一列的方法?實際情況有大約60列。 – Matt

+0

使用ConvertTo-CSV,Out-File和夾在中間的Replace,我可以輸出一個沒有引號的文件。 http://social.technet.microsoft.com/Forums/windowsserver/en-US/f6b610b6-bfb2-4140-9529-e61ad30b8927/how-to-export-csv-without-doublequote?forum=winserverpowershell – Matt

+1

($ record | (\ d {3}) - (\ d {2}) - 替換對象| (\ d {4})','$ 1 $ 2 $ 3'| Out-File $ OutFileName – mjolinor

0

FWIW - 未經測試。保留儘可能多的原始腳本。

$csvFile = "C:\Test\List.csv" 
$folderPath = Split-Path -Parent $csvFile.fullname 

Import-Csv -Path $csvFile -Delimiter "`t" | 
Where-Object {$_.LastName -ne ""} | ##Prevent importing blank lines 
Foreach-Object { 
    $_.SSN = $_.SSN -Replace "-","" ##Remove dashes from SSN 
    $saveName = $_.FirstName + " " + $_.LastName + ".csv" 
    Export-Csv $_ -Delimiter "`t" -Path $folderPath\$saveName 
    } 
+0

對於這一個,我得到以下PS提示符: cmdlet導出-Csv在命令管道位置1 以下參數的供應值: InputObject: – Matt

+0

已添加$ _以將當前管道對象用作輸出對象的輸入。 – mjolinor