PowerShell：將每行CSV導出到單個文件

Question

我有一個製表符分隔的CSV，需要將每行分割爲不同的CSV，文件名爲[FirstName] [LastName] .csv。

此外，我需要操縱一些數據，特別是從SSN中刪除破折號。

樣本含量

FirstName LastName SSN 
========= ========= ====== 
Albert  Abernathy 111-11-1111 
Billy  Barty  222-22-2222 
Chris  Canton  333-33-3333 

所需的輸出（文件名| CSV內容）

Albert Abernathy.csv | Albert  Abernathy 111111111 
Billy Barty.csv  | Billy  Barty  222222222 
Chris Canton.csv  | Chris  Canton  333333333 

這裏是我到目前爲止所。

$csvFile = "C:\Test\List.csv" 
$folderPath = Split-Path -Parent $csvFile 
$csv = Import-Csv -Path $csvFile -Delimiter "`t" 
| Where-Object {$_.LastName -ne ""} ##Prevent importing blank lines 
| Foreach-Object {$_.SSN -Replace "-","" } ##Remove dashes from SSN 
foreach ($line in $csv) 
{ $saveName = $line.FirstName + " " + $line.LastName + ".csv" 
    Export-Csv -Delimiter "`t" -Path $folderPath\$saveName 
} 

到目前爲止，所有這些都在運行，但它只是在最後一個條款之後暫停而沒有任何反應。正如我拼湊在一起，這從谷歌搜索，我敢肯定，我的語法需要工作，所以我會很感激，如果有人能在正確的方向

--Update--

信用點我alroc將我指向正確的方向，mjolinor提供了無法在其他地方找到的無價REPLACE語法。這是我的最後腳本。

$csvFile = "C:\Test\List.csv" 
$folderPath = Split-Path -Parent $csvFile 

### filter out blank records and delete dashes from SSN ### 
(Get-Content $csvFile | 
    Select-Object | 
    Where-Object {$_.LastName -ne ""}) | #Rows with non-blank last name 
    Foreach-Object {$_ -Replace '(\d{3})-(\d{2})-(\d{4})','$1$2$3'} | 
    Set-Content $csvFile 

### import csv data and export file for each row ### 
$csv = Import-Csv -Path $csvFile -Delimiter "`t" 
foreach ($row in $csv) { 
    $outPath = Join-Path -Path $folderPath -ChildPath $($row.FirstName + " " + $row.LastName + ".csv"); 
    $row | Select-Object | 
     ConvertTo-Csv -NoTypeInformation -Delimiter "`t" | 
     Foreach-Object {$_.Replace('"','')} | #Delete quotes around each "cell" 
     Out-File $outPath 
    (Get-Content $outPath | 
     Select-Object -Skip 1) | #Delete header 
     Set-Content $outPath 
} 

Answer 1

我不是你所說的「最後的條款後，只是停頓了一下，什麼也沒發生」，但它可能是與你的管路import-csv你的過程的其餘部分，並試圖指派清楚什麼結果輸入$csv。這個工作對我來說：

$csvFile = "C:\Test\List.csv" 
$folderPath = Split-Path -Parent $csvFile 
$csv = Import-Csv -Path $csvFile -Delimiter "`t" 
foreach ($record in $csv) { 
    $OutFileName = join-path -Path $folderPath -ChildPath $($record.FirstName + " " + $record.LastName + ".csv"); 
    $record|select-object FirstName,LastName,@{name="SSN";expression={$_.SSN -replace "-",""}}|export-csv -NoTypeInformation -Path $OutFileName -Delimiter "`t"; 
} 

或者，如果你想這樣做，沒有中間變量，保持更多的管道-Y：

$csvFile = "C:\Test\List.csv" 
$folderPath = Split-Path -Parent $csvFile 
Import-Csv -Path $csvFile -Delimiter "`t" | foreach { 
    $OutFileName = join-path -Path $folderPath -ChildPath $($_.FirstName + " " + $_.LastName + "2.csv"); 
    $_|select-object FirstName,LastName,@{name="SSN";expression={$_.SSN -replace "-",""}}|export-csv -NoTypeInformation -Path $OutFileName -Delimiter "`t"; 
} 

Answer 2

FWIW - 未經測試。保留儘可能多的原始腳本。

$csvFile = "C:\Test\List.csv" 
$folderPath = Split-Path -Parent $csvFile.fullname 

Import-Csv -Path $csvFile -Delimiter "`t" | 
Where-Object {$_.LastName -ne ""} | ##Prevent importing blank lines 
Foreach-Object { 
    $_.SSN = $_.SSN -Replace "-","" ##Remove dashes from SSN 
    $saveName = $_.FirstName + " " + $_.LastName + ".csv" 
    Export-Csv $_ -Delimiter "`t" -Path $folderPath\$saveName 
    }