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我開發了一個選擇表單並使用ajax調用php腳本來獲取結果,ajax正常工作併成功連接到了php,但是我無法獲得php的結果無法獲得結果表格php
這是我的表格:
<form method="post" action = "#">
<div class="functionitem" id="selector_phot">
<select name="photographer">
<option>All Photographers</option>
<option>John Baldwin</option>
<option>Wendy James</option>
<option>Ian Smith</option>
<option>Rebecca Fortesque-Smythe</option>
</select>
</div>
<div class="functionitem" id="selector_cat">
<select name="sets">
<option>All Sets</option>
<option>Ceremony</option>
<option>Lunch</option>
<option>Garden</option>
</select>
</div>
<div class="functionitem" id="viewresult"><span class="button"><span><input type="button" class="form_button" value=" View"></span></span>
</div>
<div class="functionitem" style="margin-right: 60px">
<span class="button"><span><input type="button" class="form_button" id="guestlogin" value=" Guest Login "></span></span>
</div>
<div class="functionitem">
<span class="button"><span><input type="button" class="form_button" id="register" value=" Register"></span></span>
</div>
這裏是我的PHP腳本:
if(isset($_POST['photographer'])&&isset($_POST['sets']))
{
echo "results";
}
所以它應該打印出來的結果,但它沒有做我做錯了什麼,請幫助,謝謝!
這裏是ajax代碼:
注意,爲什麼你的選項沒有價值屬性? –
你的ajax代碼在哪裏? –
似乎每一件事情都很好,發佈你的ajax代碼請 – confucius