我有一個嚴重的QtPlugin問題。我試圖從一個接口,一個名爲詞典編寫一個插件:QT插件編譯問題
class dictionary
{
private:
... some private members
public:
~dictionary();
... some no virtual methods
virtual void collectData()=0;
virtual void collectOperator()=0;
virtual void collectControl()=0;
};
QT_BEGIN_NAMESPACE
Q_DECLARE_INTERFACE(CDictionnary, "shinoe.cameleon.dictionary/2.0")
QT_END_NAMESPACE
我已經在blankdictionary項目實施的字典中聲明如下(blankdictionary.h)一blankdictionary類。
的.pro文件:
!include(../../../configuration.pri)
QT += core gui
TARGET = blanktarget
TEMPLATE = lib
CONFIG += plugin
#dictionary interface includes
!include(../../../machine/kernel/includekernel.pri)
SOURCES += blankdictionary.cpp
HEADERS += blankdictionary.h
的blankdictionary.h文件:
class blankdictionary : public dictionary {
Q_OBJECT
Q_INTERFACES(dictionary)
public:
blankdictionary();
void collectData();
void collectOperator();
void collectControl();
};
在我blankdictionary.cpp文件的末尾,我有:
QT_BEGIN_NAMESPACE
Q_EXPORT_PLUGIN2(blanktarget, blankdictionary)
QT_END_NAMESPACE
在編譯,它返回此錯誤:
blankdictionary.cpp: In function 'QObject* qt_plugin_instance()':
blankdictionary.cpp:20: error: no match for 'operator=' in '_instance = (operator new(44u), (<statement>, ((blankdictionary*)<anonymous>)))'
c:\QtSDK\Desktop\Qt\4.7.4\mingw\include/QtCore/qpointer.h:65: note: candidates are: QPointer<T>& QPointer<T>::operator=(const QPointer<T>&) [with T = QObject]
c:\QtSDK\Desktop\Qt\4.7.4\mingw\include/QtCore/qpointer.h:67: note: QPointer<T>& QPointer<T>::operator=(T*) [with T = QObject]
有什麼想法嗎?
在此先感謝!
我認爲問題來自這裏: 「[...]使通過插件的應用程序擴展包括以下步驟: 定義一組接口(只有純虛函數的類)用於交談的插件[...]「 來自此源:http://doc.qt.nokia.com/4.7-snapshot/plugins-howto.html。 所以,我認爲我必須讓字典界面只有純虛函數的類。 我現在試試。 – ocds