0
我有下表,它從我的數據庫查詢用戶,然後在每個用戶下面添加14個玩家。我在同一個數據庫表中添加了一些列,我試圖讓列回顯出來,並且拋出了一個未定義的索引錯誤,但我不完全確定我可以在這裏定義它的位置。添加一組數據庫列到數組的問題
這是我試圖讓新列回聲的部分。我有14個玩家,所以這個數組通過它們遍歷每個用戶。我加入了相同數量的「位置」所以這將是PLAYER1位置1,player2位置2,等等
for ($playerNum = 1; $playerNum <= $totalPlayerNumbers; $playerNum++) {
echo '<tr><td><div class="draftBorder">' . $playerNum . '</div></td>';
foreach ($userPlayerStore as $userPlayer) {
echo '<td><div class="draftBorder">' . $userPlayer['player' . $playerNum] . '</div></td>';
的我試圖做到這一點,這就是爲什麼我得到的錯誤...
foreach ($userPlayerStore as $userPlayer) {
echo '<td><div class="draftBorder">' . $userPlayer['player' . ' - ' . 'position' . $playerNum] . '</div></td>';
我還可以如何格式化,以便我可以在玩家旁邊顯示位置。就像這樣:
PLAYER1 - 位置1
全碼:
<?php $userPlayerStore = array(); ?>
<table class="draft_border_table">
<tr>
<th>Rnd</th>
<?php
// Output usernames as column headings
$userResults = mysqli_query($con, 'SELECT * FROM user_players ORDER BY `id`');
while($userPlayer = mysqli_fetch_array($userResults)) {
$userPlayerStore[] = $userPlayer;
echo '<th><div>' . $userPlayer['username'] . '</div></th>';
}
?>
</tr>
<?php
// Output each user's player 1-14 in each row
$totalPlayerNumbers = 14;
for ($playerNum = 1; $playerNum <= $totalPlayerNumbers; $playerNum++) {
echo '<tr><td><div class="draftBorder">' . $playerNum . '</div></td>';
foreach ($userPlayerStore as $userPlayer) {
if (empty($userPlayer['player'.$playerNum])){
$extra_class = 'emptycell';
}else{
$extra_class = 'filledcell';
}
echo '<td class="draft_table_td">' . $userPlayer['player' . $playerNum] . '</td>';
}
echo '</tr>';
}
?>
</table>
什麼是你的數據庫表結構?你目前的輸出是什麼樣的? – Kuya