我需要一些幫助來生成MS SQL 2012查詢,以匹配所需的階梯輸出。該行總結了一個日期範圍(帳戶提交日期月)的數據,列由另一個日期範圍概括它(支付日期一個月)SQL Stairstep查詢需要幫助
表1:帳戶軌道帳戶放置集合。
CREATE TABLE [dbo].[Accounts](
[AccountID] [nchar](10) NOT NULL,
[SubmissionDate] [date] NOT NULL,
[Amount] [money] NOT NULL,
CONSTRAINT [PK_Accounts] PRIMARY KEY CLUSTERED (AccountID ASC))
INSERT INTO [dbo].[Accounts] VALUES ('1000', '2012-01-01', 1999.00)
INSERT INTO [dbo].[Accounts] VALUES ('1001', '2012-01-02', 100.00)
INSERT INTO [dbo].[Accounts] VALUES ('1002', '2012-02-05', 350.00)
INSERT INTO [dbo].[Accounts] VALUES ('1003', '2012-03-01', 625.00)
INSERT INTO [dbo].[Accounts] VALUES ('1004', '2012-03-10', 50.00)
INSERT INTO [dbo].[Accounts] VALUES ('1005', '2012-03-10', 10.00)
表2:跨軌道所作的付款
CREATE TABLE [dbo].[Trans](
[TranID] [int] IDENTITY(1,1) NOT NULL,
[AccountID] [nchar](10) NOT NULL,
[TranDate] [date] NOT NULL,
[TranAmount] [money] NOT NULL,
CONSTRAINT [PK_Trans] PRIMARY KEY CLUSTERED (TranID ASC))
INSERT INTO [dbo].[Trans] VALUES (1000, '2012-01-15', 300.00)
INSERT INTO [dbo].[Trans] VALUES (1000, '2012-02-15', 300.00)
INSERT INTO [dbo].[Trans] VALUES (1000, '2012-03-15', 300.00)
INSERT INTO [dbo].[Trans] VALUES (1002, '2012-02-20', 325.00)
INSERT INTO [dbo].[Trans] VALUES (1002, '2012-04-20', 25.00)
INSERT INTO [dbo].[Trans] VALUES (1003, '2012-03-24', 625.00)
INSERT INTO [dbo].[Trans] VALUES (1004, '2012-03-28', 31.00)
INSERT INTO [dbo].[Trans] VALUES (1004, '2012-04-12', 5.00)
INSERT INTO [dbo].[Trans] VALUES (1005, '2012-04-08', 7.00)
INSERT INTO [dbo].[Trans] VALUES (1005, '2012-04-28', 3.00)
這裏的期望輸出應該是什麼樣子
*Total Payments in Each Month*
SubmissionYearMonth TotalAmount | 2012-01 2012-02 2012-03 2012-04
--------------------------------------------------------------------
2012-01 2099.00 | 300.00 300.00 300.00 0.00
2012-02 350.00 | 325.00 0.00 25.00
2012-03 685.00 | 656.00 15.00
前兩列按月總結Account.Amount分組。
最後4列爲Tran.TranAmount按月計算當前行給定月份中的賬戶。
我一直在用的查詢感覺很接近。我只是沒有正確的滯後。 這裏是我與迄今工作查詢:
Select SubmissionYearMonth,
TotalAmount,
pt.[0] AS MonthOld0,
pt.[1] AS MonthOld1,
pt.[2] AS MonthOld2,
pt.[3] AS MonthOld3,
pt.[4] AS MonthOld4,
pt.[5] AS MonthOld5,
pt.[6] AS MonthOld6,
pt.[7] AS MonthOld7,
pt.[8] AS MonthOld8,
pt.[9] AS MonthOld9,
pt.[10] AS MonthOld10,
pt.[11] AS MonthOld11,
pt.[12] AS MonthOld12,
pt.[13] AS MonthOld13
From (
SELECT Convert(Char(4),Year(SubmissionDate)) + '-' + Right('00' + Convert(VarChar(2), DatePart(Month, SubmissionDate)),2) AS SubmissionYearMonth,
SUM(Amount) AS TotalAmount
FROM Accounts
GROUP BY Convert(Char(4),Year(SubmissionDate)) + '-' + Right('00' + Convert(VarChar(2), DatePart(Month, SubmissionDate)),2)
)
AS AccountSummary
OUTER APPLY
(
SELECT *
FROM (
SELECT CASE WHEN DATEDIFF(Month, SubmissionDate, TranDate) < 13
THEN DATEDIFF(Month, SubmissionDate, TranDate)
ELSE 13
END AS PaymentMonthAge,
TranAmount
FROM Trans INNER JOIN Accounts ON Trans.AccountID = Accounts.AccountID
Where Convert(Char(4),Year(TranDate)) + '-' + Right('00' + Convert(VarChar(2), DatePart(Month, TranDate)),2)
= AccountSummary.SubmissionYearMonth
) as TransTemp
PIVOT (SUM(TranAmount)
FOR PaymentMonthAge IN ([0],
[1],
[2],
[3],
[4],
[5],
[6],
[7],
[8],
[9],
[10],
[11],
[12],
[13])) as TransPivot
) as pt
它產生的輸出如下:
SubmissionYearMonth TotalAmount MonthOld0 MonthOld1 MonthOld2 MonthOld3 ...
2012-01 2099.00 300.00 NULL NULL NULL ...
2012-02 350.00 325.00 300.00 NULL NULL ...
2012-03 685.00 656.00 NULL 300.00 NULL ...
至於列日頭。我不確定這裏最好的選擇是什麼。我可以添加一組額外的列並創建一個可以在結果報告中使用的計算值。
SQL小提琴:http://www.sqlfiddle.com/#!6/272e5/1/0
感謝您的任何援助。
**優秀的**作業,包括樣本數據和查詢。這就是每個問題應該如何寫的! – mellamokb
@mellamokb:加上一個鏈接到[SQLFiddle](http://sqlfiddle.com),它將是完美:) –
@juergend:的確。以下是OP的查詢:http://www.sqlfiddle.com/#!3/56223/1 – mellamokb