XML到Java的ArrayList的支架應用

這是我與JEE/REST應用程序的第一個項目XML到Java的ArrayList的支架應用

我的問題是，我不能讓我的服務器來解析XML後到我的對象至極包含一個ArrayList ...

這裏就是我處理@POST，服務器只返回它所得到：

Search.java

@POST 
@Consumes({MediaType.APPLICATION_XML, MediaType.APPLICATION_JSON}) 
@Produces({MediaType.APPLICATION_XML, MediaType.APPLICATION_JSON}) 
public Request returnRequest(Request input) { 
    return input; 
}

當我張貼此：

<request> 
    <name>Salle 101</name> 
    <equipments> 
     <equipment> 
      <rfName>Tableau Blanc</rfName> 
     </equipment> 
     <equipment> 
      <rfName>Video Projecteur</rfName> 
     </equipment> 
    </equipments> 
    <startslot>9</startslot> 
    <endslot>10</endslot> 
    <size>6</size> 
    <site>Toulouse</site> 
</request>

我得到這個：

<?xml version="1.0" encoding="UTF-8"?> 
<request> 
    <endslot>10</endslot> 
    <equipments/> 
    <name>Salle 101</name> 
    <site>Toulouse</site> 
    <size>6</size> 
    <startslot>9</startslot> 
</request>

正如你可以看到我沒有做我的設備清單正確返回...

這裏是我的實體文件：

Request.java

@XmlRootElement(name = "request") 
public class Request { 
    //@XmlElement 
    private String name; 
    //@XmlElement 
    private Equipments equipments; 
    //@XmlElement 
    private int startSlot; 
    //@XmlElement 
    private int endSlot; 
    //@XmlElement 
    private int size; 
    //@XmlElement 
    private String site; 

    public Request(){ 
     // my stuff 
    } 

    // getters & setters

Equipment.java

@Entity 
@Table(name = "equipment") 
@XmlRootElement 
@NamedQueries({ 
@NamedQuery(name = "Equipment.findAll", query = "SELECT e FROM Equipment e"), 
@NamedQuery(name = "Equipment.findByRfName", query = "SELECT e FROM Equipment e WHERE e.rfName = :rfName")}) 
public class Equipment implements Serializable { 

    private static final long serialVersionUID = 1L; 
    @Id 
    @Basic(optional = false) 
    @NotNull 
    @Size(min = 1, max = 20) 
    @Column(name = "RF_NAME") 
    private String rfName; 
    @OneToMany(cascade = CascadeType.ALL, mappedBy = "equipment") 
    private Collection<RoomEquipment> roomEquipmentCollection; 

    public Equipment() { 
    } 

    public Equipment(String rfName) { 
     this.rfName = rfName; 
    } 

    //...

後搜索我的一點點看到創建ArrayList的一類可能是有用的，所以在這裏它是：

Equipments.java

@XmlRootElement(name="equipments") 
public class Equipments implements Serializable { 
    private ArrayList<Equipment> equipments; 

    public Equipments(){ 
     this.equipments = new ArrayList<>(); 
    } 

    public void add(Equipment eq){ 
     this.getEquipments().add(eq); 
    } 

    public ArrayList<Equipment> getEquipments(){ 
     return this.equipments; 
    } 

    /** 
    * @param equipments the equipments to set 
    */ 
    public void setEquipments(ArrayList<Equipment> equipments) { 
     this.equipments = equipments; 
    } 

}

感謝您的幫助

來源

2015-12-28 Monstercrunch