無效列名「*******」

Question

格式此查詢確定，在調試時我看到價值更新，但只有告訴我這個消息{"Invalid column name 'Mohannad' "}，請幫我傢伙

UPDATE Employee 
SET Name =Mohannad 
, Age=22 
, GenderID =1 
, CountryID=1 
, Mobile=8765 
FROM Employee 
    INNER JOIN Country ON Employee.CountryID = Country.CountryID 
    INNER JOIN Gender ON Employee.GenderID = Gender.GenderID 
WHERE EmployeeID=1 ; 

SELECT Employee.EmployeeID, Employee.Name, Employee.Age, Employee.GenderID, Gender.GenderName, Employee.CountryID, Country.CountryName, Employee.Mobile 
FROM Employee 
    INNER JOIN Country ON Employee.CountryID = Country.CountryID 
    INNER JOIN Gender ON Employee.GenderID = Gender.GenderID 

Answer 1

你需要Mohannad周圍的報價：

SET Name='Mohannad' 

如果沒有引號，數據庫引擎會推測它是列的名稱。

如果您在程序中生成此查詢，則應該使用預準備語句，而不是僅在名稱周圍加引號以避免錯誤和注入。

Answer 2

Monhannad應該是在引號

UPDATE Employee 
SET Name = 'Mohannad', Age=22, GenderID =1, CountryID=1, Mobile=8765 
FROM Employee 
    INNER JOIN Country ON Employee.CountryID = Country.CountryID 
    INNER JOIN Gender ON Employee.GenderID = Gender.GenderID 
WHERE EmployeeID=1 ; 

Answer 3

與此代碼

SET Name='Mohannad'