Angular 2 rxjs超時回調

Question

我想在HTTP調用發生超時事件時向用戶提供反饋。

我嘗試這樣做：

return this._http 
       .post(apiUrl + 'Search/Everything', params, {withCredentials: true, headers: this.headers}) 
       .timeout(5000, this._feedbackService.error("Custom error message")) 
       .map((response: Response) => response.json().data); 

但是，只要HTTP調用時將觸發反饋服務。

超時啓動時如何啓動服務？

Answer 1

假設_feedbackService.error返回Error，你應該能夠做你需要與timeoutWith和​​運營商什麼：

import "rxjs/add/observable‌​/defer"; 
import "rxjs/add/observable‌​/throw"; 
import "rxjs/add/operator/timeoutWith"; 
import { Observable } from "rxjs/Observable‌​"; 

return this._http 
    .post(apiUrl + 'Search/Everything', params, {withCredentials: true, headers: this.headers}) 
    .timeoutWith(5000, Observable.defer(() => Observable.throw(this._feedbackService.error("Custom error message")))) 
    .map((response: Response) => response.json().data);