平等學說運營商更新查詢的設置

Question

我有問題設置基於語句

我想值激活特定uc和關閉所有其他ucs。

(uc.collection = :collectionId)應該返回true或false，以便正確處理。

的QueryBuilder：

$queryBuilder = $this->getEntityManager()->createQueryBuilder(); 
    $queryBuilder->update('TestBundle:UserCollection', 'uc') 
     ->set('uc.active', '(uc.collection = :collectionId)') 
     ->where('uc.user = :userId'); 

    $queryBuilder->setParameter('collectionId', $collectionId); 
    $queryBuilder->setParameter('userId', $userId); 

輸出DQL：

UPDATE TestBundle:UserCollection uc 
SET uc.active = (uc.collection = :collectionId) WHERE uc.user = :userId 

getSQL錯誤：

[Syntax Error] line 0, col 81: Error: Expected 
Doctrine\ORM\Query\Lexer::T_CLOSE_PARENTHESIS, got '=' 

這裏的SQL我想：

UPDATE user_collections AS uc SET uc.active = (uc.idCollections = 1) 
WHERE uc.idUsers = 74 

Answer 1

嘗試通過expr()->eq(...)表達設置它：

$queryBuilder = $this->getEntityManager()->createQueryBuilder(); 
$queryBuilder->update('TestBundle:UserCollection', 'uc') 
    ->set('uc.active', $queryBuilder->expr()->eq('uc.collection', ':collectionId')) 
    ->where('uc.user = :userId'); 

$queryBuilder->setParameter('collectionId', $collectionId); 
$queryBuilder->setParameter('userId', $userId);