MySql的像JSON領域查詢

Question

我JSON類型列在我的表

字段值的一個命名爲medium像["art", "nature"]

我想等價像查詢WHERE媒體LIKE％藝術％得到的行`

Refered這個鏈接，但無法找到該

https://dev.mysql.com/doc/refman/5.7/en/json-search-functions.html

一個妥善的解決辦法0

Answer 1

這是你的解決方案

$array = json_decode('["art","nature"]',true); 
$condition = ''; 
foreach($array as $r) $condition .= 'medium LIKE "%'.$r.'%" OR '; 
$condition = rtrim($condition,' OR '); 
echo $condition; 
echo 'SELECT * FROM table WHERE '.$condition;