我想通過用戶模型獲取當前用戶,但它返回null。laravel 5.4如何通過用戶模型獲取當前用戶?和Auth :: user()不工作
$user = new User;
//$user = Auth::user();
$product = new Product;
$product->user_id = $user->user_id;
$product->save();
這是我得到 Integrity constraint violation: 1048 Column 'user_id' cannot be null
當我試圖驗證得到它::用戶(),它給了同樣的錯誤。
這是我的自定義登錄控制器..
public function auth(Request $request)
{
$this->validate($request, [
'email' => 'required|email|max:255',
'password' => 'required|min:6',
]);
$data = $request->only('email', 'password');
if (Auth::attempt($data)) {
$email = $request->email;
$users = DB::table('users')
->where('email', $email)
->select('users.*', 'user_name')
->get();
Session::put('set', $users);
if ($users[0]->is_admin == '1') {
return redirect()->intended('adminDashboard');
}else{
return redirect()->intended('dashboard');
}
}else{
return back()->withInput()->witherrors(['Email or password did not match!']);
}
}
有什麼不對的代碼?
請提供'登錄Controller'代碼。你做了很多不必要的事情 –
你可以在問題中看到登錄控制器。 –