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我已成功設置基於LDAPS容器的身份驗證,並且現在正嘗試使用Spring安全性來處理它,因爲我還需要執行查找/查詢。WAS 6.1上使用Spring Security的LDAP SSL
在我有所有的端點使用正確的密鑰庫(WC_DefaulHost除外)。另外,我還爲ldaps,主機,端口設置了動態端點配置。
當我嘗試登錄時,我剛剛收到「spring_security_login?login_error」並且沒有system.out異常。
我錯過了什麼嗎?端點配置是否不夠?任何方式,我可以得到更多的信息來解決問題?
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd">
<authentication-manager>
<authentication-provider ref="ldapAuthProvider" />
</authentication-manager>
<beans:bean id="contextSource"
class="org.springframework.security.ldap.DefaultSpringSecurityContextSource">
<!-- AD authenticator -->
<beans:constructor-arg value="ldaps://host:port/DC=" />
<beans:property name="userDn" value="CN=,OU=,DC=" />
<beans:property name="password" value="" />
</beans:bean>
<beans:bean id="ldapAuthProvider"
class="org.springframework.security.ldap.authentication.LdapAuthenticationProvider">
<beans:constructor-arg>
<beans:bean id="wimLdapAuthenticator"
class="org.springframework.security.ldap.authentication.BindAuthenticator">
<beans:constructor-arg ref="contextSource" />
<beans:property name="userSearch">
<beans:bean id="userSearch"
class="org.springframework.security.ldap.search.FilterBasedLdapUserSearch">
<beans:constructor-arg index="0" value="" />
<beans:constructor-arg index="1" value="CN={0}" />
<beans:constructor-arg index="2" ref="contextSource" />
</beans:bean>
</beans:property>
</beans:bean>
</beans:constructor-arg>
</beans:bean>
<http auto-config="true" pattern="/**">
<!-- Security zones -->
<intercept-url pattern="/**" access="IS_AUTHENTICATED_FULLY" />
<intercept-url pattern="/spring_security_login" access="IS_AUTHENTICATED_ANONYMOUSLY" />
</http>
</beans:beans>