我創建一個AsyncTask來登錄用戶到服務器。登錄工作正常,但如果他離開空字段的用戶可以登錄..我怎樣才能改變這樣的空白登錄也是錯誤login..any幫助將是不錯的感謝AsyncTask用mysql登錄
package com.app.app;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.List;
import com.app.app.library.DatabaseHandler;
import com.app.app.library.JSONParser;
import com.app.app.library.UserFunctions;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONException;
import org.json.JSONObject;
import com.app.app.DashboardActivity;
import com.app.app.R;
import com.app.app.R.id;
import android.app.ProgressDialog;
import android.content.Context;
import android.content.Intent;
import android.content.SharedPreferences;
import android.os.AsyncTask;
import android.preference.PreferenceManager;
import android.util.Log;
import android.view.ViewGroup;
import android.widget.Button;
import android.widget.CheckBox;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.Toast;
public class LoginTask extends AsyncTask<String, Void, Integer> {
private ProgressDialog progressDialog;
private LoginActivity activity;
private int id = -1;
private com.app.app.library.JSONParser jsonParser;
private static String loginURL = "http://10.0.2.2/android/";
private static String registerURL = "http://10.0.2.2/android/";
private static String KEY_SUCCESS = "success";
private static String KEY_ERROR = "error";
private static String KEY_ERROR_MSG = "error_msg";
private static String KEY_UID = "uid";
private static String KEY_NAME = "name";
private static String KEY_EMAIL = "email";
private static String KEY_CREATED_AT = "created_at";
private int responseCode = 0;
public LoginTask(LoginActivity activity, ProgressDialog progressDialog)
{
this.activity = activity;
this.progressDialog = progressDialog;
}
@Override
protected void onPreExecute()
{
progressDialog.show();
}
protected Integer doInBackground(String... arg0) {
EditText userName = (EditText)activity.findViewById(R.id.loginEmail);
EditText passwordEdit = (EditText)activity.findViewById(R.id.loginPassword);
String email = userName.getText().toString();
String password = passwordEdit.getText().toString();
UserFunctions userFunction = new UserFunctions();
JSONObject json = userFunction.loginUser(email, password);
// check for login response
try {
if (json.getString(KEY_SUCCESS) != null) {
String res = json.getString(KEY_SUCCESS);
if(Integer.parseInt(res) == 1){
//user successfully logged in
// Store user details in SQLite Database
DatabaseHandler db = new DatabaseHandler(activity.getApplicationContext());
JSONObject json_user = json.getJSONObject("user");
//Log.v("name", json_user.getString(KEY_NAME));
// Clear all previous data in database
userFunction.logoutUser(activity.getApplicationContext());
db.addUser(json_user.getString(KEY_NAME), json_user.getString(KEY_EMAIL),
json.getString(KEY_UID), json_user.getString(KEY_CREATED_AT));
responseCode = 1;
// Close Login Screen
//finish();
}else{
responseCode = 0;
// Error in login
}
}
} catch (NullPointerException e) {
e.printStackTrace();
}
catch (JSONException e) {
e.printStackTrace();
}
return responseCode;
}
@Override
protected void onPostExecute(Integer responseCode)
{
EditText userName = (EditText)activity.findViewById(R.id.loginEmail);
EditText passwordEdit = (EditText)activity.findViewById(R.id.loginPassword);
if (responseCode == 1) {
progressDialog.dismiss();
Intent i = new Intent();
i.setClass(activity.getApplicationContext(), DashboardActivity.class);
activity.startActivity(i);
//activity.loginReport(responseCode);
}
else {
progressDialog.dismiss();
activity.showLoginError(responseCode);
}
}
}
'loginUser'方法的代碼在哪裏?在用戶名/電子郵件和密碼上清理輸入... – hovanessyan