我們怎樣才能得到VARRAY從IN參數的過程

Question

我是新來的PL/SQL ...在Varray我怎麼能從IN參數獲得多個值..... else有沒有另外的方法來獲得值...

我想interate通過VARRAY值...如果任何其他選項，然後它很好.. 編碼：

CREATE OR REPLACE 
PROCEDURE dynamic_query_build(
    vr_plan_sku_id IN VARCHAR2) 
IS 
type plan_sku_id_array IS VARRAY(999) OF VARCHAR2(5000); 
plan_sku_id plan_sku_id_array; 
total   INTEGER; 
vrx_plan_sku_id VARCHAR2(3000); 
BEGIN 
    vrx_plan_sku_id:= REPLACE(vr_plan_sku_id,',',chr(39)||','||chr(39)); 
    plan_sku_id := plan_sku_id_array(chr(39)||vrx_plan_sku_id||chr(39)); 
    total   := plan_sku_id.count; 
    FOR i   IN 1 .. total 
    LOOP 
    dbms_output.put_line(plan_sku_id(i)); 
    END LOOP; 
EXCEPTION 
WHEN OTHERS THEN 
    raise_application_error(-20001,'An error was encountered - '||SQLCODE||' -ERROR- '||SQLERRM); 
END dynamic_query_build; 

執行：

set serveroutput on; 
declare 
vr_plan_sku_id varchar2(200) := '5863314,5863315'; 
BEGIN 
    dynamic_query_build(vr_plan_sku_id); 
END; 
/

我的輸出：

anonymous block completed 
'5863314','5863315' 

預期輸出：

5863314 
5863315 

現在它正在考慮爲單獨的值....

Answer 1

我使用過程dynamic_query_build創建了匿名塊。增加了代碼，將VARCHAR2變量分解爲varray。 我認爲，您的問題的關鍵是這一行 - plan_sku_id.EXTEND（）; 您可以動態擴展varray，但只能達到定義的最大值（在您的情況下爲999）。

DECLARE 
vr_plan_sku_id varchar2(200) := '5863314,5863315'; 
PROCEDURE dynamic_query_build(
    vr_plan_sku_id IN VARCHAR2) 
IS 
type plan_sku_id_array IS VARRAY(999) OF VARCHAR2(5000); 
plan_sku_id plan_sku_id_array; 
total   INTEGER; 

position PLS_INTEGER := 0; 
last_position PLS_INTEGER := 1; 
tmp VARCHAR2(5000); 
counter PLS_INTEGER := 1; 
BEGIN 
    plan_sku_id := plan_sku_id_array(); 
    LOOP 
    position := INSTR(vr_plan_sku_id, ',', last_position); 
    IF position > 0 THEN 
     tmp := SUBSTR(vr_plan_sku_id, last_position, position - last_position); 
     last_position := position + 1; 
    ELSE 
     tmp := SUBSTR(vr_plan_sku_id, last_position); 
    END IF; 
    plan_sku_id.EXTEND(); 
    plan_sku_id(counter) := tmp; 
    counter := counter + 1; 
    EXIT WHEN position = 0 OR counter > 10; 
    END LOOP; 
    total   := plan_sku_id.count; 
    FOR i   IN 1 .. total 
    LOOP 
    dbms_output.put_line(plan_sku_id(i)); 
    END LOOP; 
EXCEPTION 
WHEN OTHERS THEN 
    raise_application_error(-20001,'An error was encountered - '||SQLCODE||' -ERROR- '||SQLERRM); 
END dynamic_query_build; 
BEGIN 
    dynamic_query_build(vr_plan_sku_id); 
END; 
/

Answer 2

放入DBMS_OUTPUT語句替換這將消除字符串中的引號

 .... 
    dbms_output.put_line replace (replace (plan_sku_id(i), ''''))',',chr(10); 
    .....