堆疊的離散值的直方圖

具有像堆疊的離散值的直方圖

OrderedDict([(734242, [1, 0, 1]), (734243, [0, 0, 1]), (734244, [0, 0, 0]), (734245, [3, 0, 1]), (734246, [0, 0, 0]), (734247, [0, 0, 0]), (734248, [0, 0, 0]), (734249, [0, 0, 0]), (734250, [0, 0, 0]), (734251, [0, 0, 0]), (734252, [0, 0, 0]), (734253, [0, 0, 0]), (734254, [0, 0, 0]), (734255, [0, 0, 0]), (734256, [0, 0, 0]), (734257, [0, 0, 0]), (734258, [0, 0, 0]), (734259, [1, 0, 0]), (734260, [0, 0, 0]), (734261, [0, 0, 0]), (734262, [0, 0, 0]), (734263, [0, 0, 0]), (734264, [0, 0, 0]), (734265, [0, 0, 0]), (734266, [0, 0, 0]), (734267, [0, 0, 0]), (734268, [0, 0, 0]), (734269, [0, 0, 0]), (734270, [0, 0, 0]), (734271, [0, 0, 0]), (734272, [0, 0, 0]), (734273, [0, 0, 0]), (734274, [0, 0, 0]), (734275, [0, 0, 0]), (734276, [0, 0, 0]), (734277, [0, 0, 0]), (734278, [0, 0, 0]), (734279, [0, 0, 0]), (734280, [0, 0, 0]), (734281, [0, 0, 0]), (734282, [0, 0, 0]), (734283, [0, 0, 0]), (734284, [0, 0, 0]), (734285, [0, 0, 0]), (734286, [0, 0, 0]), (734287, [0, 0, 0]), (734288, [1, 0, 0])]) 某些數據（其已經是一個堆疊樣型直方圖），

我將如何創建與此類似

堆疊直方圖

但是x軸上的值取自OrderedDict的關鍵點，並且在該關鍵點處找到的值作爲單個堆疊段的高度？

例如，(734245, [3, 0, 1])應該使matplotlib在x座標734245處顯示一個高度爲3的條，然後在其頂部顯示一段高度爲0（不可見）的高度爲1的頂點，最後的4號高度。

輸入數據可能變大，大約有10k x的座標，所以性能很重要。

歡迎任何圖書館，matplotlib不是強制性的。

來源

2016-10-15 Flavius

'''類繪圖儀： DEF get_stacked_histo_plot（個體，數據，顏色）： globalplot =無對XPOS，瓦爾斯在data.items（）： p_ampl = 0 爲binnum，l_ampl在枚舉（瓦爾斯）（xpos-0.5，p_ampl），（xpos-0.5，l_ampl + p_ampl），（xpos + 0.5，l_ampl + p_ampl），（xpos + 0.5，p_ampl）]，rgbcolor = colors [binnum]：[0124] ） p_ampl = l_ampl + p_ampl 如果globalplot： globalplot + = p 其他： globalplot = p 返回globalplot''' – Flavius

（使用sagemath）的作品，但我想知道如果它可能是做得更好 – Flavius

這是一種非常低效的做事方式，但它可以幫助您開始。

a = dict([(734242, [1, 0, 1]), (734243, [0, 0, 1]), (734244, [0, 0, 
0]), (734245, [3, 0, 1]), (734246, [0, 0, 0]), (734247, [0, 0, 0]), 
(734248, [0, 0, 0]), (734249, [0, 0, 0]), (734250, [0, 0, 0]), (734251, 
[0, 0, 0]), (734252, [0, 0, 0]), (734253, [0, 0, 0]), (734254, [0, 0, 
0]), (734255, [0, 0, 0]), (734256, [0, 0, 0]), (734257, [0, 0, 0]), 
(734258, [0, 0, 0]), (734259, [1, 0, 0]), (734260, [0, 0, 0]), (734261, 
[0, 0, 0]), (734262, [0, 0, 0]), (734263, [0, 0, 0]), (734264, [0, 0, 
0]), (734265, [0, 0, 0]), (734266, [0, 0, 0]), (734267, [0, 0, 0]), 
(734268, [0, 0, 0]), (734269, [0, 0, 0]), (734270, [0, 0, 0]), (734271, 
[0, 0, 0]), (734272, [0, 0, 0]), (734273, [0, 0, 0]), (734274, [0, 0, 
0]), (734275, [0, 0, 0]), (734276, [0, 0, 0]), (734277, [0, 0, 0]), 
(734278, [0, 0, 0]), (734279, [0, 0, 0]), (734280, [0, 0, 0]), (734281, 
[0, 0, 0]), (734282, [0, 0, 0]), (734283, [0, 0, 0]), (734284, [0, 0, 
0]), (734285, [0, 0, 0]), (734286, [0, 0, 0]), (734287, [0, 0, 0]), 
(734288, [1, 0, 0])]) 


for b in a: 
    plt.bar(x=b, height=a[b][0], color='r') 
    plt.bar(x=b, height=a[b][1], bottom=a[b][0], color='b') 
    plt.bar(x=b, height=a[b][2], bottom=a[b][1], color='g')

爲了提高效率，你必須改變你的字典到一個數組。所有參數x=，height=和bottom=都可以採用數組作爲參數。然後您可以將代碼減少到3 plt.bar()調用。

來源

2016-10-16 19:14:48

堆疊的離散值的直方圖

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