SQL表左外聯接結果組通過

購買數量從3張發票是50 + 100 + 50 = 200和

出售數量從1張發票是10

我使用下面的代碼用於獲取結果作爲

Total Purchase - Total Sale = Closing Qty 
    200  -  10 = 290

，但我得到錯誤的結果如圖所示連接圖像：

請指引我糾正我的代碼

SELECT 
    P.PRODUCT as PRODUCTNAME, 
    P.QUANTITY AS PURCHASE, 
    ISNULL(S.QUANTITY, 0) AS SALE, 
    ISNULL(P.QUANTITY, 0) - ISNULL(s.QUANTITY, 0) AS CLOSINGQTY 
FROM 
    [PurchaseData] P 
LEFT OUTER JOIN 
    [DeliveryData1] S ON P.Product = s.PRODUCT

來源

2016-10-08 Ashfaque Baig

你想要什麼表格結果？ –

對於SQL問題，您應該始終標記您的DBMS。 –

當與來自不同表的聚集工作，不加入的表和彙總，然後，但總量第一，加入骨料：

select 
    p.product as productname, 
    p.sum_quantity as purchase, 
    coalesce(s.sum_quantity, 0) as sale, 
    p.sum_quantity - coalesce(s.sum_quantity, 0) as closingqty 
from 
(
    select product, sum(quantity) as sum_quantity 
    from purchasedata 
    group by product 
) p 
left join 
(
    select product, sum(quantity) as sum_quantity 
    from deliverydata1 
    group by product 
) s on s.product = p.product;

我已經更換了ifnull與3210，所以查詢完全標準的SQL兼容。

來源

2016-10-08 21:23:50

感謝Thorsten ........現在查詢工作正如預期的結果.....再次感謝很多 –

如果你想你應該

 SELECT 
     P.PRODUCT as PRODUCTNAME, 
     sum(P.QUANTITY AS PURCHASE), 
     sum(isnull(S.QUANTITY,0)) AS SALE, 
     sum(isnull(P.QUANTITY,0))-sum(isnull(s.QUANTITY,0)) AS CLOSINGQTY 

    FROM [PurchaseData] P LEFT OUTER JOIN [DeliveryData1] S ON P.Product = s.PRODUCT 
    GROUP BY P.PRODUCT

來源

2016-10-08 20:07:53 scaisEdge

如果我理解正確的使用和與組最終的結果，你有問題因爲您有一個給定產品的多個購買記錄。如果是這樣的話，那麼就聚集之前的JOIN：

SELECT p.*, COALESCE(S.QUANTITY, 0) AS SALE, 
     COALESCE(P.QUANTITY, 0)-COALESCE(s.QUANTITY, 0) AS CLOSINGQTY 
FROM (SELECT p.product, p.quantity 
     FROM PurchaseData P 
     GROUP BY p.product 
    ) p LEFT OUTER JOIN 
    DeliveryData1 S 
    ON P.product = s.producct;

其實，我不清楚這兩個表中有重複的 - 或者，即使兩個做。所以，你可能需要爲S做類似的事情。

來源

2016-10-08 20:07:55

SQL表左外聯接結果組通過

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