我正在學習C++我從教科書中複製了這段代碼,在編譯代碼時,最後出現錯誤。錯誤說:錯誤:控制到達非空函數結束
Control Reaches end of non-void function
其位於代碼的末尾:
#include "ComplexNumber.hpp"
#include <cmath>
ComplexNumber::ComplexNumber()
{
mRealPart = 0.0;
mImaginaryPart = 0.0;
}
ComplexNumber::ComplexNumber(double x, double y)
{
mRealPart = x;
mImaginaryPart = y;
}
double ComplexNumber::CalculateModulus() const
{
return sqrt(mRealPart*mRealPart+
mImaginaryPart*mImaginaryPart);
}
double ComplexNumber::CalculateArgument() const
{
return atan2(mImaginaryPart, mRealPart);
}
ComplexNumber ComplexNumber::CalculatePower(double n) const
{
double modulus = CalculateModulus();
double argument = CalculateArgument();
double mod_of_result = pow(modulus, n);
double arg_of_result = argument*n;
double real_part = mod_of_result*cos(arg_of_result);
double imag_part = mod_of_result*sin(arg_of_result);
ComplexNumber z(real_part, imag_part);
return z;
}
ComplexNumber& ComplexNumber::operator=(const ComplexNumber& z)
{
mRealPart = z.mRealPart;
mImaginaryPart = z.mImaginaryPart;
return *this;
}
ComplexNumber ComplexNumber::operator-() const
{
ComplexNumber w;
w.mRealPart = -mRealPart;
w.mImaginaryPart = -mImaginaryPart;
return w;
}
ComplexNumber ComplexNumber::operator+(const ComplexNumber& z) const
{
ComplexNumber w;
w.mRealPart = mRealPart + z.mRealPart;
w.mImaginaryPart = mImaginaryPart + z.mImaginaryPart;
return w;
}
std::ostream& operator<<(std::ostream& output,
const ComplexNumber& z)
{
output << "(" << z.mRealPart << " ";
if (z.mImaginaryPart >= 0.0)
{
output << " + " << z.mImaginaryPart << "i)";
}
else
{
output << "- " << -z.mImaginaryPart << "i)";
}
} //-------->>>>**"Control Reaches end of non-void function"**
無論這本書是從哪裏來的,我都不會想象它是那麼好。 – chris
這本書是由喬·皮特·弗朗西斯和喬納森·懷特利編寫的。 「C++科學計算指南」。我正在閱讀它,因爲我應該使用面向對象的方法進行一些數值計算,而且這是我能找到的唯一一個,如果您有任何建議,我會很高興聽到他們的聲音。 –
說實話,科學家和*好的編程不會很好地結合在一起。如果你對這門語言有足夠的瞭解並且不習慣壞習慣,那麼你最終會從那些不是爲了教授這門語言而設計的書籍中獲得更多。對於該語言,我們有一個不錯的[書籍]列表(http://stackoverflow.com/questions/388242/the-definitive-c-book-guide-and-list)。 – chris