減少嘗試的次數，除了python

Question

我正在寫一個類似於診斷程序的程序，該程序運行一個測試，然後基於那個做更多的測試，所以這些大部分都在`try,except之內完成，並且有相當多的他們中的很多。有沒有其他方法可以達到這個目的，但減少try except的數量？

這裏是一個示例代碼。

try: 
    treeinfo = subprocess.check_output(['C:\Python27\Scripts\scons.bat','-f' ,'scons_default.py' ,'--tree=all']) 
    print "\n" 
    print "Your machine type is ",platform.machine() 
     print "Compiling using default compiler\n" 
    print treeinfo 

except subprocess.CalledProcessError as e: 
    print "ERROR\n" 

try: 
    with open ('helloworld.exe')as f: 
     subprocess.call('helloworld.exe') 
     print"Build success" 
     log64 = subprocess.check_output(["dumpbin", "/HEADERS", "helloworld.exe"]) 
     if arch64 in log64: 
      print "Architecture of the compiled file is 64-bit " 
     elif arch32 in log64: 
      print "Architecture of the compiled file is 32-bit" 
except IOError as e: 
    print "Build failed\n" 


print "\n" 

上面的同一個代碼（使用不同的文件名）重複，我知道這不是一個好的做法。我對python非常陌生，並且使用Google搜索沒有給出任何有用的結果。

Answer 1

您可以將邏輯分成不同的功能，並在try塊打電話給他們一個接一個：

def a(): 
    treeinfo = subprocess.check_output(['C:\Python27\Scripts\scons.bat','-f' ,'scons_default.py' ,'--tree=all']) 
    print "\n" 
    print "Your machine type is ",platform.machine() 
    print "Compiling using default compiler\n" 
    print treeinfo 

def b(): 
    subprocess.call('helloworld.exe') 
    print"Build success" 

def c(): 
    log64 = subprocess.check_output(["dumpbin", "/HEADERS", "helloworld.exe"]) 
    if arch64 in log64: 
     print "Architecture of the compiled file is 64-bit " 
    elif arch32 in log64: 
     print "Architecture of the compiled file is 32-bit" 

def try_these(funs, catch): 
    for fun in funs: 
     try: 
      fun() 
     except catch: 
      print 'ERROR!' 

try_these([a, b, c], catch=(IOError, OSError)) 

其中「釣」你要處理異常的元組。