如何在Zend 1中創建查詢並從查詢中獲取結果？

Question

我試圖在查看查詢，執行它並獲得結果。 這是我的嘗試：

$last_id = $_COOKIE['last_id']; 
//if (isset($last_id)){ 
$db = new Zend_Db_Table('order_products_names'); //the table name 
$query = "select * from order_products_names where order_id = '$last_id'"; 
$query = $db->query($query); 
while ($row = $query->fetch()) { 
    echo $row['names']; 
} 

顯然它不起作用。有人可以幫我弄這個嗎 ？ 我也試過這個版本：

$db = new Zend_Db_Adapter_Pdo_Mysql(array(
       'host'  => 'localhost', 
       'username' => 'lunchbox_live', 
       'password' => 'xxxxxxxxxxxx', 
       'dbname' => 'order_products_names', 
       'adapterNamespace' => 'MyProject_Db_Adapter' 
)); 
$last_id = $_COOKIE['last_id']; 
$dbAdapter = Zend_Db_Table::getDefaultAdapter(); 
$query = $dbAdapter->query("select * from order_products_names where order_id = '$last_id'"; 

這發生在這行代碼（$query = $dbAdapter->query("select * from order_products_names where order_id = '$last_id'";）的評論： 和發生這種情況時，不評論說：

Answer 1

嘗試：

$db = Zend_Db_Table::getDefaultAdapter(); 
$row = $db->fetchRow("SELECT * FROM order_products_names where order_id = '". $last_id . "'"); 
echo $row['names']; 

Answer 2

這不是一個好辦法做事情，但只是爲了回答你的問題，嘗試這樣的事情：

$db = new Zend_Db_Adapter_Pdo_Mysql(array(
       'host'  => 'localhost', 
       'username' => 'lunchbox_live', 
       'password' => 'xxxxxxxxxxxx', 
       'dbname' => 'order_products_names', 
       'adapterNamespace' => 'MyProject_Db_Adapter' 
)); 

$last_id = $_COOKIE['last_id']; 
$stmt = $db->query("select * from order_products_names where order_id = ?", array($last_id)); 
$products = $stmt->fetchAll(); 

foreach($products as $product) 
{ 
//.... 
}