搜索引擎

IM在一個簡單的搜索引擎的工作，我有什麼工作正常，但我想改變這行代碼：搜索引擎

$query = "SELECT * FROM mobiles WHERE (`name` LIKE '%".$search."%') or (`type` LIKE '%".$search."%')";

到

$query = "SELECT * FROM mobiles WHERE (`name` LIKE '%:search%') or (`type` LIKE '%:search%')";

但對於一些原因這是行不通的

以下是完整的PHP代碼

<?php 
require("../login/connect.php"); 
$search = $_GET['query']; 

$query = "SELECT * FROM mobiles WHERE (`name` LIKE '%".$search."%') or (`type` LIKE '%".$search."%')"; 


$query_params = array(':search' => $_GET['query']); 

try 
{ 
    $stmt = $db->prepare($query); 
    $result = $stmt->execute($query_params); 
} 
catch(PDOException $ex) 
{ 
    die("Failed to run query: " . $ex->getMessage()); 
} 

$rows = $stmt->fetchAll(); 

$min_length = 3; 
if(strlen($query) >= $min_length) 
{ 
    echo "<table border='0' width='600' align='center' cellpadding='1'>"; 
    echo "<tr align='center' bgcolor='#03acfa' > 
      <td height='35px' width='200px'><b>Mobile Name</b></td> 
      <td><b>Mobile Type</b></td> 
     </tr>"; 

    foreach($rows as $row): 
    { 
     echo "<tr align='center' bgcolor='#93dafb'> 
       <td height='25px'>". $row['name'] ."</td> <td>".$row['type']."</td> 
      </tr>" ; 
    } 
    endforeach; 
}

來源

2014-07-16 Alberto

搜索引擎？.. –

變化

$query_params = array(':search' => $_GET['query']);

到

$query_params = array(':search' => "%".$search."%");

，現在你可以在使用本查詢

(`name` LIKE :search) or (`type` LIKE :search)";

來源

2014-07-16 22:46:27

綁定不能像這樣部分。你必須在查詢中使用LIKE :search，然後你要綁定變量裏面包括%小號

來源

2014-07-16 21:36:41 developerwjk

您的意思是該查詢需要看起來像「SELECT * FROM mobiles WHERE（'name' LIKE：search）or（''''LIKE：search）」; – Alberto

回答

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