如何執行一個功能，如果手動刷新

索引頁的設計是這樣tat它通過jquery請求登錄後檢索數據...我的懷疑是tat如何維護頁面，如果手動刷新被執行或可以我執行任何功能，如果手動刷新執行？下面是我的一些代碼..如何執行一個功能，如果手動刷新

Checklogin.php

<?php 
      session_start(); 
      include('dbconnect.php'); 
      $email=mysql_real_escape_string($_REQUEST['email']); 
      $pass=mysql_real_escape_string($_REQUEST['pass']); 
      $pass=filter_var($pass, FILTER_SANITIZE_STRING); 
      $email=filter_var($email, FILTER_SANITIZE_EMAIL); 
      $query="SELECT * from `users` WHERE `email`='$email' and `pass`='$pass'"; 
      $res=mysql_query($query) or die("Error in query"); 
      $res1=mysql_num_rows($res); 
      $name="guest"; 
      if($res1 == 0) 
      {  
      $query="SELECT * from `users` WHERE `email`='$email'"; 
      $res=mysql_query($query) or die("Error in query"); 
      $res2=mysql_num_rows($res); 
      if($res2>0){ 
     $code=3; 
     echo json_encode(array('name'=>$name,'code'=>$code)); 
      } 
      else{ 
     $code=2; 
     echo json_encode(array('name'=>$name,'code'=>$code)); 
      } 
     } 
     else 
     { 
    $code=1; 
    $row = mysql_fetch_assoc($res); 
    $name=$row['name']; 
    $_SESSION['email']=$email; 
    $_SESSION['name']=$name; 
    $query="select * from crown1 where email='".$_SESSION['email']."';"; 
        $res=mysqli_query($con,$query); 
        $row=mysqli_fetch_array($res); 
        $level=$row['level']; 
        $points=$row['points']; 
        $rank=$row['rank']; 
        $times="time".$level; 
        $timest=$row[$times]; 
        $query="select * from qna where level=".$level.";"; 
        $res9=mysqli_query($con,$query); 
        $row9=mysqli_fetch_array($res9); 
        $title=$row9['title']; 
        $qn=$row9['qnlink']; 
        $_SESSION['title']=$title; 
        $_SESSION['qnlink']=$qn; 
        $_SESSION['level']=$level; 
        $_SESSION['points']=$points; 
        $_SESSION['timest']=$timest; 
        $_SESSION['rank']=$rank; 

    //echo $_SESSION['email']; 
    echo json_encode(array('name'=>$_SESSION['name'],'code'=>$code)); 

    } 
?>

leader.js

var loadData = function(){ 
     var url = 'Leaders.php'; 
     $.getJSON(url, function(data) { 
     $('#Leaders').empty().append('<ul style="position: absolute; margin: 0px; padding: 0px; top: 0px; list-style-type:none; width:100%">'); 
     $.each(data, function(index, data) { 
      $('#Leaders>ul').append("<li style='margin: 0px; padding: 0px; height: 30px; width:100%'>&nbsp; #"+data.rank+" &nbsp;&nbsp;"+data.name+"<span class='myNumber' name='n1' style='float:right;'> "+data.points+" &nbsp;</span></li>"); 
     }); 
      $('#Leaders').append('</ul>'); 
    }); 
     var url = 'Game.php'; 
     $.getJSON(url, function(data) { 
     $('#points').empty().append(data.points); 
     $('#level').empty().append(data.level); 
     $('#ranking').empty().append(data.rank); 
     $('#levelUsers').empty().append(data.users); 
     $('#totalPlayers').empty().append(data.nousers); 
     $('#titlediv>div>h3>center').empty().append(data.title); 
     $('#game3').empty().append("<img src='"+data.qnlink+"' style='width:700px;height:250px;'/>"); 
     //setIntervalOnce(loadData, 5000); 
     }); 
}

我打電話LoadData（）Checklogin被稱爲後...

來源

2014-01-16 Sharukh Mohamed

_manual refresh_？你的意思是通過瀏覽器刷新按鈕？ – putvande

這看起來像是你只是想在運行一個函數，如果頁面加載和用戶登錄。爲什麼特別是如果瀏覽器手動重新加載？ –

是的...因爲所有我通過此LoadData（）加載的內容丟失，頁面變爲空白...即在刷新 –

沒有辦法100％檢測頁面是手動加載還是不加載，因爲用於確定此信息的信息總是可能被欺騙，如果有人真的想要。但你可以這樣做：

if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') { 
    /* Page was loaded via AJAX */ 
} else { 
    /* Page wasn't loaded via AJAX, e.g. direct url entered, page refreshed, referred from another page. */ 
}

來源

2014-01-16 15:40:24 Ryan

如何執行一個功能，如果手動刷新

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