IP的正確Count訪問

Question

此查詢...

SELECT a.* 
FROM LicenseHistory a 
JOIN (
    SELECT LicenseID, date as date, COUNT(DISTINCT IPAddress) as IPcount 
    FROM LicenseHistory 
    WHERE (LicenseID= 24965) 
    GROUP BY LicenseID,IPAddress,Date 
    /*HAVING COUNT(DISTINCT IPAddress) > 1*/ 
) b ON (a.LicenseID = b.LicenseID) AND date(a.date) = date(b.date) 
order by date desc, LicenseID desc 

回報......

Date    lic  users IP Address country Count 
2013-05-14 13:44:56 24965 15 70.60.96.98 US 1455 
2013-05-14 13:44:56 24965 15 70.60.96.98 US 1455 
2013-05-14 11:50:34 24965 15 72.252.247.148 JM 111 
2013-05-14 11:50:34 24965 15 72.252.247.148 JM 111 
2013-03-29 07:40:37 24965 15 184.39.241.223 US 14 

計列顯然是不正確，因爲查詢只提取不同IP的回報率的計數123（對於70.60.96.98）。這個查詢如何到達1455的計數？我想統計2013年5月14日許可證24965從70.60.96.98到達的次數，以及每個日期的列表中每個ip的類似程度。

Answer 1

爲什麼如此令人髮指的複雜查詢時

SELECT count(*) 
FROM LicenseHistory 
WHERE (LicenseID = 24965) AND (IPAddress = '70.60.96.98') 

會做的伎倆？