如何從字符串

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刪除字符串我有這個字符串如何從字符串

<?xml version="1.0" encoding="utf-8"?> 
<string xmlns="http://tempuri.org/">{"IsSuccess":true,"Result":"","Obj": 
[{"FACULTY_CODE":1,"FACULTY_DESC":"\u0E1A\u0E23\u0E34\u0E2B\u0E32\u0E23\u0E18\u0E38\u0E23\u0 
E01\u0E34\u0E08","FACULTY_DESC_ENG":"Faculty of Business 
Administration","FACULTY_CODE_ICL":"00039","FACULTY_GROUP":"1000"}, 
{"FACULTY_CODE":2,"FACULTY_DESC":"\u0E19\u0E34\u0E15\u0E34\u0E28\u0E32\u0E2A\u0E15\u0E23\u0E 
4C","FACULTY_DESC_ENG":"Faculty of Law","FACULTY_CODE_ICL":"00037","FACULTY_GROUP":"0101"}, 
{"FACULTY_CODE":3,"FACULTY_DESC":"\u0E28\u0E34\u0E25\u0E1B\u0E28\u0E32\u0E2A\u0E15\u0E23\u0E 
4C","FACULTY_DESC_ENG":"Faculty of Liberal 
Arts","FACULTY_CODE_ICL":"00096","FACULTY_GROUP":"0100"}, 
{"FACULTY_CODE":4,"FACULTY_DESC":"\u0E27\u0E34\u0E17\u0E22\u0E32\u0E28\u0E32\u0E2A\u0E15\u0E 
23\u0E4C\u0E41\u0E25\u0E30\u0E40\u0E17\u0E04\u0E42\u0E19\u0E42\u0E25\u0E22\u0E35","FACULTY_D 
ESC_ENG":"Faculty of Science and 
Technology","FACULTY_CODE_ICL":"00083","FACULTY_GROUP":"0303"}, 
{"FACULTY_CODE":5,"FACULTY_DESC":"\u0E23\u0E31\u0E10\u0E28\u0E32\u0E2A\u0E15\u0E23\u0E4C","F 
ACULTY_DESC_ENG":"Faculty of Political 
Sciences","FACULTY_CODE_ICL":"00068","FACULTY_GROUP":"0101"}, 
{"FACULTY_CODE":7,"FACULTY_DESC":"\u0E19\u0E34\u0E40\u0E17\u0E28\u0E28\u0E32\u0E2A\u0E15\u0E 
23\u0E4C","FACULTY_DESC_ENG":"Faculty of Communication 
Arts","FACULTY_CODE_ICL":"00038","FACULTY_GROUP":"0104"}, 
{"FACULTY_CODE":8,"FACULTY_DESC":"\u0E27\u0E34\u0E17\u0E22\u0E32\u0E25\u0E31\u0E22\u0E19\u0E 
32\u0E19\u0E32\u0E0A\u0E32\u0E15\u0E34\u0E14\u0E34\u0E29\u0E22\u0E30\u0E28\u0E23\u0E34\u0E19 
","FACULTY_DESC_ENG":"Didyasarin International 
College","FACULTY_CODE_ICL":"00137","FACULTY_GROUP":""}, 
{"FACULTY_CODE":9,"FACULTY_DESC":".","FACULTY_DESC_ENG":"Bachelor of Fine and Applied 
Art","FACULTY_CODE_ICL":"","FACULTY_GROUP":""}]}</string>

但我想刪除"<?xml version="1.0" encoding="utf-8"?> <string xmlns="http://tempuri.org/">"和"</string>"

我使用這個代碼

NSError *error = NULL; 
    NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"{.+}" options:0 error:&error]; 
    NSArray *matches = [regex matchesInString:dataString options:0 range:NSMakeRange(0, [dataString length])]; 
NSLog(@"matches = %@",matches); 
for (NSTextCheckingResult *match in matches) { 
    NSRange matchRange = [match range]; 
    newDataString = [dataString substringWithRange:matchRange]; 
}

它不工作。

來源

2013-04-22 user2298882

你是什麼意思是削減？ – anthonybell 2013-04-22 03:28:29

你是什麼意思「它不工作」 – sosborn 2013-04-22 03:28:42

什麼你可以簡單地做是

NSString *string1 = @"<?xml version=\"1.0\" encoding=\"utf-8\"?> <string xmlns=\"http://tempuri.org/\">"; 
NSString *string2 = @"</string>"; 
NSString *myString;//this is your string 
myString = [myString stringByReplacingOccurrencesOfString:string1 withString:@""]; 
myString = [myString stringByReplacingOccurrencesOfString:string2 withString:@""];

來源

2013-04-23 10:35:47 Raj

你可以使用正則表達式，像這樣：

%s/\"[^"]+\":\s*\" *\"\(\s*,\s*\)*//g

這是一個gvim的正則表達式

這將擺脫每個鍵值對，其中值是「」或「」取出的逗號，如果它有

來源

2013-04-22 03:33:37 anthonybell

如何從字符串

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