你可以通過源代碼(django.db.model.query),那麼你就會很清楚,這裏的Django的1.3.4的query.py,
def __getitem__(self, k):
"""
Retrieves an item or slice from the set of results.
"""
if not isinstance(k, (slice, int, long)):
raise TypeError
assert ((not isinstance(k, slice) and (k >= 0))
or (isinstance(k, slice) and (k.start is None or k.start >= 0)
and (k.stop is None or k.stop >= 0))), \
"Negative indexing is not supported."
if self._result_cache is not None:
if self._iter is not None:
# The result cache has only been partially populated, so we may
# need to fill it out a bit more.
if isinstance(k, slice):
if k.stop is not None:
# Some people insist on passing in strings here.
bound = int(k.stop)
else:
bound = None
else:
bound = k + 1
if len(self._result_cache) < bound:
self._fill_cache(bound - len(self._result_cache))
return self._result_cache[k]
if isinstance(k, slice):
qs = self._clone()
if k.start is not None:
start = int(k.start)
else:
start = None
if k.stop is not None:
stop = int(k.stop)
else:
stop = None
qs.query.set_limits(start, stop)
return k.step and list(qs)[::k.step] or qs
try:
qs = self._clone()
qs.query.set_limits(k, k + 1)
return list(qs)[0]
except self.model.DoesNotExist, e:
raise IndexError(e.args)
當你不通過迭代查詢集,_result_cache是無,那麼當你調用RESC [0],它只會跳到下面幾行,
try:
qs = self._clone()
qs.query.set_limits(k, k + 1)
return list(qs)[0]
except self.model.DoesNotExist, e:
raise IndexError(e.args)
你會發現,在這種情況下,_result_cache沒有被設置。這就是爲什麼多個resc [0]的持續時間是同一時間的原因。
調用LEN(RESC)後,你可以找到源代碼,
def __len__(self):
# Since __len__ is called quite frequently (for example, as part of
# list(qs), we make some effort here to be as efficient as possible
# whilst not messing up any existing iterators against the QuerySet.
if self._result_cache is None:
if self._iter:
self._result_cache = list(self._iter)
else:
self._result_cache = list(self.iterator())
elif self._iter:
self._result_cache.extend(self._iter)
return len(self._result_cache)
你可以看到_result_cache具有價值,那麼你調用區域經濟共同體[0],它只會使用緩存,
if self._result_cache is not None:
....
return self._result_cache[k]
源代碼永遠不會說謊,所以最好在你沒有在文檔中找到你的答案時閱讀源代碼。
不錯的挖! + –
謝謝你這樣一個徹底的答案。 – shanusmagnus