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怎麼回事,像這樣的查詢在MySQL工作(在5.6現在):MySQL的順序由後分組工作意外
SELECT node.name, (COUNT(parent.name) - 1) AS depth
FROM nested_category AS node,
nested_category AS parent
WHERE node.lft BETWEEN parent.lft AND parent.rgt
GROUP BY node.name
ORDER BY node.lft;
我很困惑,我習慣了SQL Server時,它會抱怨node.lft是不是在選定列的列表中,但在這裏,在MySQL它的偉大工程,
我感謝您的幫助,
優秀的答案!非常感謝。 – Alex