我有這個疑問按名稱排序,並通過最流行的標題 - 甲骨文
select movie_name, user_name
from movie natural join movie_queue natural join users
group by (movie_name, user_name)
order by movie_name;
那滴類似下面的一個列表:
MOVIE_NAME USER_NAME
------------------------------------------------------- ------------------------
E.T. the Extra-Terrestrial Cris
E.T. the Extra-Terrestrial Elizabeth
E.T. the Extra-Terrestrial John
E.T. the Extra-Terrestrial Mary
E.T. the Extra-Terrestrial Peter
Indiana Jones and the Kingdom of the Crystal Skull Elizabeth
Indiana Jones and the Kingdom of the Crystal Skull John
Indiana Jones and the Kingdom of the Crystal Skull Mary
Jurassic Park Elizabeth
Jurassic Park John
Jurassic Park Mary
Jurassic Park Peter
Signs Elizabeth
The Sixth Sense Mary
Unbreakable John
Unbreakable Mary
Unbreakable Peter
War of the Worlds Elizabeth
War of the Worlds John
War of the Worlds Mary
War of the Worlds Peter
問題是如何我是按行排名還是按movie_name排序?
我目前正在通過movie_name訂購清單,但我也想從 最受歡迎的電影訂購到不太受歡迎的電影。
期望的結果:
結果, 「ET外星人」行應該首先出現,因爲它出現在表次數多了,「第六感」應該最後出現在「符號」之後。因爲兩部最後的電影都只出現一次,但S在T之前。
我試着添加這個: order by count(movie_name),movie_name;
但我仍然沒有得到我想要的結果。 在結束電影要組織這樣
這是我希望他們來組織:從比較吃香的不太受歡迎,並按照字母順序提前
MOVIE_NAME USER_NAME
------------------------------------------------------- ------------------------
E.T. the Extra-Terrestrial Cris
E.T. the Extra-Terrestrial Elizabeth
E.T. the Extra-Terrestrial John
E.T. the Extra-Terrestrial Mary
E.T. the Extra-Terrestrial Peter
Jurassic Park Elizabeth
Jurassic Park John
Jurassic Park Mary
Jurassic Park Peter
War of the Worlds Elizabeth
War of the Worlds John
War of the Worlds Mary
War of the Worlds Peter
Indiana Jones and the Kingdom of the Crystal Skull Elizabeth
Indiana Jones and the Kingdom of the Crystal Skull John
Indiana Jones and the Kingdom of the Crystal Skull Mary
Unbreakable John
Unbreakable Mary
Unbreakable Peter
Signs Elizabeth
The Sixth Sense Mary
感謝
@Burhan,謝謝!我明白了,我可以有多列,我試圖count(movie_name)作爲第二列,但我仍然沒有得到我想要的結果。我需要它把最受歡迎的電影放在第一位(流行是基於更多的行)。 – Cristy 2012-07-22 23:10:39