在Windows Phone 7中寫入XML文檔

Question

我試圖從一個對象寫入一些數據到一個XML文檔，然後在線教程，但是我遇到了一個我似乎無法理解的問題，我使用的啓動文件的創建using (XmlWriter writer = XmlWriter.Create("myData.xml"))，我得到一個錯誤的「myData.xml」的代碼，我得到的錯誤是：

The best overload method match for 'System.Xml.XmlWriter.Create(System.Xml.XmlWriter)' 
has some invalid arguments 

Argument 1: cannot convert from 'string' to 'System.Xml.XmlWriter' 

是隨着Windows Phone的XmlWriter兼容？如果不是，我將不得不改變寫入文件的大量代碼嗎？

編輯：這是我的代碼

 string output = SerializeToString<AppData>(rulesData); 

     using (XmlWriter writer = XmlWriter.Create(output)) 
     { 
      writer.WriteStartDocument(); 
      writer.WriteStartElement("myData"); 

      writer.WriteElementString("Starting Cash", rulesData.myStartingCash); 
      writer.WriteElementString("Land on Go Data", rulesData.myLandOnGo); 
      writer.WriteElementString("Free Parking Data", rulesData.myFreeParking); 
      writer.WriteElementString("Full Circuit Data", rulesData.myFullCircuit); 
      writer.WriteElementString("Auction Data", rulesData.myAuction); 
      writer.Flush(); 

      writer.WriteEndElement(); 
      writer.WriteEndDocument(); 
     } 

謝謝！ -Ryan

Answer 1

您可以使用此代碼：

public static void SerializeToStream<T>(Stream stream, object model) 
    { 
     var writer = XmlWriter.Create(stream); 
     var s = new XmlSerializer(typeof(T)); 
     s.Serialize(writer, model); 
    } 

    public static string SerializeToString<T>(object model) 
    { 
     var xmlSer = new XmlSerializer(typeof(T)); 

     using (var stream = new MemoryStream()) 
     { 
      SerializeToStream<T>(stream, model); 
      var s = stream.ToArray(); 
      return System.Text.Encoding.UTF8.GetString(s, 0, s.Length); 
     } 
    } 

    public static void SerializeToFile<T>(string filename, object model) 
    { 
     using (FileStream stream = File.Open(filename, FileMode.Create)) 
     { 
      SerializeToStream<T>(stream, model); 
     } 
    } 

您的代碼不編譯，因爲你傳遞一個字符串而不是流的XmlWriter

用法：

string output = SerializeToString<ClassName>(instanceOfClass);