面向對象的PHP返回數據庫行和訪問數組元素

我是面向對象PHP概念的新手（在www.killerphp.com上的教程之後），我打算將所有的php應用程序遷移到OO PHP。
我開始根據「where」條件設置的方法「setSecurity（）」基於對象屬性從數據庫中讀取授權級別。面向對象的PHP返回數據庫行和訪問數組元素

我設法返回數組「getSecurity（）」，但打印輸出將給：

security Object 
(
    [secArray] => Array 
     (
      [from_date1] => 1992-01-01 
      [to_date1] => 0000-00-00 
      [from_date2] => 1992-01-01 
      [to_date2] => 0000-00-00 
      [view] => 1 
      [insert] => 0 
      [update] => 1 
      [delete] => 1 
      [valid] => 1 
     ) 

) 
/*"Array 1"*/

我的問題是我不熟悉的打印輸出到一個正常的數組（下面）。

Array 
(
    [from_date1] => 1992-01-01 
    [to_date1] => 0000-00-00 
    [from_date2] => 1992-01-01 
    [to_date2] => 0000-00-00 
    [view] => 1 
    [insert] => 0 
    [update] => 1 
    [delete] => 1 
    [valid] => 1 
) 
/*"Array 2"*/

我的問題是： 1）如何可以訪問我的數組從getSecurity元素（）方法（從Array 1）？
2）如何讓我的方法正確返回數組（與數組2相同）？

代碼片段在下面找到。

非常感謝您的任何支持...

'test.php的'

<?php 
include("connect.php"); 
include("security.php"); 
$secArray=new security(); 
$secArray->setSecurity('test_user',1,1,1,$link); 
$secArray->getSecurity(); 
echo "<pre>"; print_r($secArray); echo "</pre>"; 
?>

'security.php'

<?php 
class security 
{ 
    public $secArray = array(); 

    function setSecurity($user,$appid,$funid,$objid,$conn='') 
    { 
     $query="SELECT lu.DATE1 as from_date1, 
        lu.DATE2 as to_date1, 
        ga.DATE1 as from_date2, 
        ga.DATE2 as to_date2, 
        ga.VIEW as view, 
        ga.INSERT as insert, 
        ga.UPDATE as update, 
        ga.DELETE as delete, 
        ob.VALID as valid 
       FROM 
        user as lu 
        inner join group as ug on lu.GRP_ID = ug.ID 
        inner join privileges as ga on lu.GRP_ID = ga.GRP_ID 
        and ug.ID = ga.GRP_ID 
        inner join level1 as ob on ob.APP_ID = ga.APP_ID 
        and ob.FUN_ID = ga.FUN_ID 
        and ob.ID = ga.OBJ_ID 
       where 
        USERID = '$user' 
       and ga.APP_ID = $appid 
       and ga.FUN_ID = $funid 
       and ga.OBJ_ID = $objid"; 
     $result = mysql_query($query,$conn); 
     $row = mysql_fetch_assoc($result); 
     $this->secArray=$row; 
    } 

    function getSecurity() 
    { 
     return $this->secArray; 
    }  
} 
?>

來源

2012-05-06 yhammad

'$ secArray-> secArray ['from_date1']'等等。 –

getter返回的值所以撥打$secArray->getSecurity();並不能真正幫助您，除非您使用返回的值進行操作。 $mySecurity=$secArray->getSecurity();use $mySecurity...

請閱讀有關訪問數組和對象的PHP文檔。

來源

2012-05-07 14:31:17 Samson

謝謝Marc和RADU的大力協助 – yhammad

面向對象的PHP返回數據庫行和訪問數組元素

回答

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